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How many seats does a Saturn VUE have?

Saturn Vue Has The 2 Front Seats And Also The Rear Seats Which Can Hold Up To 3 People By Law...


Can the 3 rear seats be changed over with the 2 middle seats on a Kia Sedona?

http://wiki.answers.com/Q/Can_the_3_rear_seats_be_changed_over_with_the_2_middle_seats_on_a_Kia_Sedona"


How many seats does a BMW m3 have?

3. Two front seats and one rear seat (that holds two people).


How many seats does a 1939 Chrysler Imperial Coupe have?

1 bench seat for 2-3 people. no rear seat.it has 2 seats


How many people fit in a Lincoln navigator?

if you have two bench seats in the rear it can hold 8 (2-3-3) people but if you have captain seats it will only hold 7 (2-2-3)


How do you prove that a2 - 6a plus 9 is a perfect square?

a2 - 6a + 9 = a2 - 3a - 3a + 9 = a(a - 3) - 3(a - 3) = (a - 3)*(a - 3) = (a - 3)2


Can you convert 2006 Saturn ion back seat from 2 seats with seatbelts to 3?

Yes. Get the rear seats and belts from a 4 door sedan Saturn Ion.


Is a Kia carens a 7 seater car?

Yes the Kia Carens is. The two rear seats fold flat. The boot space with the rear seats upright is enough to fit 3 large shopping bags (the big Blue Bags Tesco), side by side.


When a2 plus a-3 is subtracted from 3a2-5 the answer is?

5a+3a2a2= 8a a2


What is the Proof of the derivative of the third root of x?

You can easily derive it from formula for the derivative of a power, if you remember that the cubic root of x is equal to x1/3. This question asks for the proof of the derivative, not the derivative itself. Using the definition of derivative, lim f(x) as h approaches 0 where f(x) = (f(a+h)-f(a))/h, we get the following: [(a+h)1/3 - a1/3]/h Complete the cube with (a2 + ab + b2) Multiply by [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] This completes the cube in the numerator, resulting in the following: (a + h - a) / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h cancels 1 / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] Now that we have a function that is continuous for all h, we can evaluate the limit by plugging in 0 for h. This gives 1/[a2/3 + a1/3 × a1/3 + a2/3] Simplify a1/3 × a1/3 1/[a2/3 + a2/3 + a2/3] (1/3)a2/3 or (1/3)a-2/3 This agrees with the Power Rule.


What is a formula which would add A1 A2 and A3 and divide by 3?

To add the 3 cells and divide the total by 3, you could do it several ways: =(A1+A2+A3)/3 =SUM(A1:A3)/3 =SUM(A1,A2,A3)/3


A2 plus 3 equals 12?

a=3