Let the number of boys in class X = a,
The number of girls will be a+3,
Let the number of boys in class X = a, The number of girls will be a+3,
The total number of students is a+a+3=11
2a+3=11
2a=11-3
2a=8
a=8/2
a=4
Therefore, the number of boys is 4, the number of girls will be 4+3 which will be 7. Please let me know if you understand. Thanks.
A student may fail mathematics because he/she did not study, did not attend class, or did not understand the lesson material.
A student may fail mathematics because he/she did not study, did not attend class, or did not understand the lesson material.
5
48
25% if 13 is a fractional number. You cannot have a fractional number of students.
fourteen students offers physics only.
Well, isn't that just lovely? So in this class, we have a total of 28 students. Now, if we look at the boys, we have 12 of them. To find the fraction of the class that are boys, we simply need to divide the number of boys by the total number of students. So, 12 boys out of 28 students gives us a fraction of 12/28, which can be simplified to 3/7. Happy little fractions!
This information tells us that (248/x) = (62/100) , by the definition of percentage. Thus x = 248*(100/62) = 400 so there are 400 students in the class.
about 25
8/15
Using set theory let A contain the students who failed mathematics (50) and B contain the students that failed English (30). Now set A and B intersect so they share the same students (5). Therefore the students who passed both subjects is the complement of the union of the sets. ~(AUB)=~(A+B-AintersectB)=100-(50+30-5)=25 students.
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