# Mchl Hlbrk # Ndr Hlbrk # Michael Halbrook # Indira Halbrook
6
To find the grams of Sn formed, we first need to calculate the number of moles of SnO2 in 12.5 grams. Then, we use the stoichiometry of the reaction to relate the number of moles of SnO2 to the number of moles of Sn. Finally, we convert the moles of Sn to grams using the molar mass of Sn.
The oxidation number of Sn changes from +4 in SnCl4 to +2 in SnCl2, resulting in a decrease of 2.
The balanced chemical equation shows a 1:1 ratio between Sn and SnF2. Since Sn is limiting in this reaction, the maximum amount of SnF2 that can be produced will be equal to the amount of Sn used, which is 0.480 moles. Therefore, 0.480 moles of SnF2 can be produced.
It forms SnCl2 . It is called Stannous Chloride
The product of MnO2 plus Sn(OH)4 is Mn(OH)4 and SnO2.
The chemical equation is:Zn + SnSO4 = ZnSO4 + Sn
Sn4+ is fully oxidised, Sn2+ only half
Call Colt with the sn and they will tell you.
the balanced equation is Na2S2O3 plus H2O2 yields 2NaOH plus H2S2O3 plus O2.
The chemical equation is:Sn + 4 HNO3 = SnO2 + 4 NO2 + 2 H2O
At any local gunstore. (In Soviet Russia gun sells you!)