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1 is the loneliest number per Randy Nguyen
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∙ 15y ago
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What is the formula for euqated monthly installment of loan amount?
Emi = l * r * ((1 + r)^n / (1 + r)^n - 1) * 1/12 where l = loan amt r = rate of interest n = no of terms
What is the formula to calculate mortgage payment?
The answer: you probably don't want to know. Here it is: P = L[c(1 + c)n]/[(1 + c)n- 1] where P equals payment, L equals loan amount, n equals number of months in the loan term and c equals monthly interest rate. If you are just wanting to calculate what a monthly mortgage payment would be, there are several mortgage calculators available online. Here's a link to a good one: http://www.bankrate.com/calculators/mortgages/mortgage-calculator.aspx
What is a C E L N loan?
Continuing Education Loan (private)
Formula for recurring deposit?
R.D.=P*n+P(n+1)/2400
What is the formula for PVIFA?
PVIFA = (1 - 1 / (1 + r)n) / r where n is the number of payment periods; r is the nominal interest rate for one period
Why is it said that poisson distribution is a limiting case of binomial distribution?
This browser is totally bloody useless for mathematical display but...The probability function of the binomial distribution is P(X = r) = (nCr)*p^r*(1-p)^(n-r) where nCr =n!/[r!(n-r)!]Let n -> infinity while np = L, a constant, so that p = L/nthenP(X = r) = lim as n -> infinity of n*(n-1)*...*(n-k+1)/r! * (L/n)^r * (1 - L/n)^(n-r)= lim as n -> infinity of {n^r - O[(n)^(k-1)]}/r! * (L^r/n^r) * (1 - L/n)^(n-r)= lim as n -> infinity of 1/r! * (L^r) * (1 - L/n)^(n-r) (cancelling out n^r and removing O(n)^(r-1) as being insignificantly smaller than the denominator, n^r)= lim as n -> infinity of (L^r) / r! * (1 - L/n)^(n-r)Now lim n -> infinity of (1 - L/n)^n = e^(-L)and lim n -> infinity of (1 - L/n)^r = lim (1 - 0)^r = 1lim as n -> infinity of (1 - L/n)^(n-r) = e^(-L)So P(X = r) = L^r * e^(-L)/r! which is the probability function of the Poisson distribution with parameter L.
What does the formula n(1-R)L mean?
n(1-R)L is an expression: it is not a formula.
Values of n l and ml of 2p orbital?
n : 2 l : 1 ml : -1, 0, or 1
How many possible values for l and ml are there when n equals 4?
(N-1)=(4-1)= N=3 l=0,1,2,3
Prove that the sequence n does not converge?
If the sequence (n) converges to a limit L then, by definition, for any eps>0 there exists a number N such |n-L|N. However if eps=0.5 then whatever value of N we chose we find that whenever n>max{N,L}+1, |n-L|=n-L>1>eps. Proving the first statement false by contradiction.
What are the principal quantum number and the azimuthal quantum number in an atom of Potassium?
Potassium has an electronic configuration of 1s2, 2s2, 2p6, 3s2, 3p6, 4s1 The azimuthal quantum number of 0corresonds to an s subshell, 1 p subshell You can see that you have n=1, l=0 n=2, l=0; n=2, l=1 n=3, l=0; n=3, l=1, n=4, l=0
How many sublevels are in the N 3 level?
I guess I should explain a little bit...l can take any integral value up to (n-1). So if n=1, l can only have one possible value- namely 0.l=(n-1)So if n=1, l is 0.If n=2, l is 0,1 0=s 1=p 2=d3=f
What is the formula for euqated monthly installment of loan amount?
Emi = l * r * ((1 + r)^n / (1 + r)^n - 1) * 1/12 where l = loan amt r = rate of interest n = no of terms
Longest common subsequence problem program in c?
#include<stdio.h> #include<string.h> int max(int a,int b) { return a>b?a:b; }//end max() int main() { char a[]="xyxxzxyzxy"; char b[]="zxzyyzxxyxxz"; int n = strlen(a); int m = strlen(b); int i,j; for(i=n;i>=1;i--) a[i] = a[i-1]; for(i=m;i>=1;i--) b[i] = b[i-1]; int l[n+1][m+1]; printf("\n\t"); for(i=0;i<=n;i++) { for(j=0;j<=m;j++) { if(i==0 j==0) l[i][j]=0; else if(a[i] == b[j] ) l[i][j] = l[i-1][j-1] + 1; else l[i][j] = max(l[i][j-1],l[i-1][j]); printf("%d |",l[i][j]); } printf("\n\t"); } printf("Length of Longest Common Subsequence = %d\n",l[n][m]); return 0; }
What is 1I the L N?
1 is the lonliest number
What is the sum of the arithmetic sequence?
The sum of an arithmetical sequence whose nth term is U(n) = a + (n-1)*d is S(n) = 1/2*n*[2a + (n-1)d] or 1/2*n(a + l) where l is the last term in the sequence.
Can the set of quantum numbers occur n3 l3 ml2?
no because L cannot equal n. L = (n-1)
