This is your math problem that you are supposed to solve! You are supposed to use the formula, the square of the hypotenuse is equal to the sums of the squares of the other two sides. What is your hypotenuse? It is the 32 meter long rope. Then the distance from the flagpole to the end of the rope is 12 meters. So if you take the 32 meter hypotenuse and square it. And then you can take the 12 and square it. Then you can subtract the length of the end of the rope out from the flag pole squared from the length of the rope or hypotenuse squared and have the length of the flagpole squared. Now do your math.
0.8 acres = about 3,237.5 square meters. (3,237.48514 square meters)
350 meters = 1.73983934 furlong
dont understand your question... are you asking for a VOLUME? Because the length of 24 m cubed.... is .... 24 meters. 24 meters high, 24 meters wide, and 24 meters wide. If you are looking for cubic meters... then use V= L x W x H.... or 24 x 24 x 24 = 13,824 cubic meters.
A very big area. That is a square of 2236 meters length and 2236 meters width.
194 centimeters are in 1.94 meters.
A flagpole!A flagpole!A flagpole!A flagpole!
in meters
If a cat that has a mass of 4.50 kilograms sits on a ledge that is 0.800 meters above ground and it jumps down to the ground, it will have a specific amount of kinetic energy just as it reaches the ground. In this instance, the answer would be 35.3J.
Meters obviously meters is a very good measuringtool and a flagpole is pretty high so you keep stacking itThe Answer Is Meters
Approx. 33.5 m To solve you use Pythagorean Theorem: c2 = a2 + b2 , where c is the hypotenuse of the right triangle. In this case c will be the length of the guy wire. The length of one leg of the triangle will 10m and the other will be 32m (40m - 8m) So, c2 = (10m)2 + (32m)2 c2 = 100m2 + 1024m2 = 1124m2 c = SQRT (1124m2) or c = 33.53 m
To find the height of the flagpole, you can use the concept of similar triangles. The ratio of the height of the flagpole to the length of its shadow should equal the ratio of the height of the meter stick (1 meter) to its shadow (1.4 meters). Therefore, the height of the flagpole can be calculated as follows: [ \text{Height of flagpole} = \frac{7.7 , \text{m}}{1.4 , \text{m}} \times 1 , \text{m} \approx 5.5 , \text{m}. ] Thus, the flagpole is approximately 5.5 meters tall.
I would use Meters
The Turning Torso, the third tallest residental building in Europe, reaches 190.4 meters above ground.
The total distance traveled by the ball when it reaches the ground is 24 meters. The ball travels 8 meters as it falls, and then bounces back half the distance (4 meters) and continues this pattern until it reaches the ground.
600 centimeters equals 6 meters
t matters how much mass the ball has
It depends on the relative height of the flagpole. If it's short, like a flag mast on a boat or building, probably feet and inches would do. If it's very tall, like the flagpole on top of a building or monument, yards and feet might be more appropriate.