i guess the answer is 54. A group of three digits can be selected from the 5 digits in 9 ways and each group can be arranged in 3! (i.e., 6) ways respectively and hence the answer is 6*9=54
A check number typically consists of one to three digits.
Ten digits
for new account its 13 digits...
An American Express card has 15 digits.
An American Express card has 15 digits.
6
32C3 = 4960
Six combinations: 123, 132, 213, 231, 312, 321
Only 1. In a combination, the order of the digits does not matter.
100! / 97! = 100 * 99 * 98 = 970200
10,000.
45
To find the number of three-digit combinations, we consider the digits from 000 to 999. Each digit can range from 0 to 9, giving us 10 options for each of the three digits. Therefore, the total number of three-digit combinations is (10 \times 10 \times 10 = 1,000).
5040, assuming none of the digits are the same. (Assuming they're not, there's 5040 unique combinations you can make out of 7 digits).
100C3= 100x99x98/3!= 161700 The notation is 100 choose 3
Assuming you are treating each number as a number and not as an individual unit, the numbers you can make from these digits are 899, 989 and 998.
017, 071, 107, 170, 701, 710. 6 combinations