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You can solve this problem algebraically:

(X) + (X+1) + (X+2) + (X+3) = 3990

4X + 6 = 3990

4X + 6 - 6 = 3990 - 6

4X = 3984

4X/4 = 3984/4

X = 996

Therefore, the 4 numbers are

996, 997, 998, 999

996 + 997 + 998 + 999 = 3990

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13y ago
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Shashwat Gupta

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2y ago

996 + 997 + 998 + 999

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Q: The sum of four consecutive 3 digit numbers is3990 what are the 4 numbers?
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