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The chance of one tail (on a fair coin - i.e. it's not weighted or biased) is 0.5

Using the AND rule, which means the probability of two things BOTH happening means the two probabilities are multiplied. So the chance of a tail on coin 1 AND a tail on coin 2 is 0.5 x 0.5 = 0.25

The chance of 3 tails 0.5 x 0.5 x 0.5 = 0.125

The chance of 4 tails 0.5 x 0.5 x 0.5 x 0.5 = 0.0625

So your answer is 0.0625

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Explain Mutually exclusive event?

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Related Questions

What is the probability of tossing 3 coins and getting 3 tails?

It is (1/2)3 = 1/8


What is the probability of tossing a coin and getting an even number?

Zero. Since coins land on Heads or Tails and not numbers.


Tossing 4 coins and getting tails each time?

The probability for that is (1/2)4 = 1/16.


What is the probability of tossing four coins and getting tails on all four?

Assuming it is a fair coin, the probability is 1/24 = 1/16.


What is sample space for tossing 2 coins?

The sample space for tossing 2 coins is (H = Heads & T = Tails): HH, HT, TH, TT


What is the probability of tossing a coin and getting a tails?

50% chance.


What is the number of possible outcomes when tossing 4 coins at once?

When tossing 4 coins at once, each coin has 2 possible outcomes: heads (H) or tails (T). Therefore, the total number of possible outcomes can be calculated as (2^4), which equals 16. This means there are 16 different combinations of heads and tails when tossing 4 coins.


What is the probability of tossing three coins and having exactly two of them show tails?

2 out of 8


How many possible outcomes when tossing 3 coins?

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What is the experimental probability of getting tails on a coin toss after tossing it 100 times and getting tails 60 times?

It is 60/100 = 0.6


What is the probability of tossing a coin 5 times and getting all tails?

The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 ≈ 3.13%


What is the probability of tossing seven coins and getting 6 heads?

The probability of getting only one tails is (1/2)7. With seven permutations of which flip is the tails, this gives a probability of: P(six heads in seven flips) = 7*(1/2)7 = 7/128