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The expression 2x2x2x2x5 simplifies to 80. This is because when multiplying numbers with the same base, you add the exponents. In this case, 2 is being multiplied 4 times, so 2^4 equals 16. Then you multiply 16 by 5 to get the final answer of 80.

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Related Questions

What prime facorizations go into 80?

Prime factorization of 80 = 2x2x2x2x5.


What is the product and prime number of 80?

The prime factorization of 80 is 2x2x2x2x5 (or 24x5).


Express 80 as a product of its prime numbers?

80 as a product of prime numbers can be expressed as: 2x2x2x2x5


What is the exponential form of 2x2x2x2x5?

2X * 2X * 2X * 2X5 multiply the coefficients together and add the exponents = 168 ---------


What is 540 and 80 expressed as a product of their prime factors?

Prime factorization of 540 = 2x2x3x3x3x5 Prime factorization of 80 = 2x2x2x2x5


What is 80 as product of prime factors?

2 x 2 x 2 x 2 x 5 = 80


What is the lowest fraction of 63 over 80?

63/80 is in lowest terms. 80=2x2x2x2x5 2 and 5 do not got into 63 without a remainder.


What is the least common multiple of 20 8 and 16?

The least common multiple of 8, 16, and 20 is 80.


What is the greatest common factor of 80 and 102?

The GCF of 80 and 102 is 2. The factor tree explains this. The factorization of 80 is 2x2x2x2x5. The factorization of 102 is 2x3x17. You then compare the 2 factorizations and then multiply the numbers they both have in common, but only by the number of times they appear. So the answer is 2, because it shows up in both factorizations and it shows up only once in the factorization of 102.


What is the lcm of 25 and 80?

To find the LCM of two numbers, you first break them into their prime factors. In this case, we have 25 and 80, which are broken down into: 25 = 5x5 80 = 2x2x2x2x5 The next step is to identify any common factors. Both numbers have a 5 as a prime factor, so we can discard one of these. That leaves us with 5, 5, 2, 2, 2 and 2. Multiply all these together: 2x2x2x2x5x5 = 400 Thus the LCM of 25 and 80 is 400.


How do you simplify the square root of 720?

First you have to find the factors of 720... 2, 2, 2, 2, 3, 3, 5 So basically you have sqrt(2x2x2x2x3x3x5) If you notice that you have 24 and 32 Whenever you have something under the square root you can take it out of the square root if you have two of that number. since you have 2 threes can you can take out 2 threes and you have this... 3 times sqrt(2x2x2x2x5) remember to not square the 3 when its outside the sqrt. now you have to recognize that you have two 22s. so you have take out one of them... 2 times 2 times 3 times sqrt(5) so sqrt(720) = 12sqrt(5) I know it can get confusing. Just practice at it and you'll get it.


What is 80 as the product of its prime factor?

To express 80 as the product of its prime factors, we start by dividing 80 by the smallest prime number, which is 2. 80 ÷ 2 = 40. Then, we divide 40 by 2 again to get 20. Continuing this process, we find that 80 can be expressed as 2 x 2 x 2 x 2 x 5, or 2^4 x 5.