Credit Risk. Credit risk or default risk evolves from the possibility that one of the parties to a derivative contract will not satisfy its financial obligations under the derivative contract.
Yes.
the derivative market means the the price of particular product in the market is fluctuating time by time.
A derivative is a contract with financial performance that is derived from the performance of something else. That "something else" is an underlying asset commonly termed "the underlying" and may be another financial instrument, another derivative, or an index of some kind.
Derivatives market is the market where derivative products are traded. It has a great demand all over the world with the US Derivatives market being the largest in the world. The prices of derivative products are determined based on the price movement of the underlying asset. Derivatives are extremely risky and are not for the novice investors. Some of the derivative products that are available in the derivatives market are: a. Futures b. Forwards c. Options d. Swaps e. Swap Options f. Basket Trades g. etc
well if you're finding the derivative with respect to x, it would be -tx^(-t-1)
This question refers to the combined gas law: (P1V1)/T1=(P2V2)/T2, where P is pressure, V is volume, and T is temperature in Kelvins.To solve for T1, rearrange the equation to isolate T1.T1=(P1V1T2)/(P2V2)
A T1 is 1.5Mbps. A T3 or DS3 is 45 Mbps. THere are 28 T1's in a DS3. T1 Internet Services http://www.intelletrace.com/internet-services/T1-Internet-Service.html DS3 or T3 Internet Services http://www.intelletrace.com/internet-services/DS3-Internet-Services.html
If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"
T1 transmits at about 1550 kilo bits per second; T3 around 6500 kbps.
4e^t+cos(t)
Assume that the expression is: y = 9e^(t) Remember that the derivative of e^(t) with respect to t is e^(t). If we take the derivative of the function y, we have.. dy/dt = 9 d[e^(t)]/dt = 9e^(t) Note that I factor out the constant 9. If we keep the 9 in the brackets, then the solution doesn't make a difference.
d/dt cot (t) dt = - cosec2(t)
Some good T1 providers are AT&T, BellSouth, CavTel, Cogent, New Edge Networks, Qwest and Tel West. All of these companies off high quality T1 services.
Delta is a symbol meaning "change". Delta T means (T2-T1)
^E+W=Q.....................1 Q2-Q1/Q2=T2-T1/T2.....................2 W=Q2-Q1 Given W/Q =T2-T1/T2 T2-T1=^T and Q=^W ^w/Q=^T/T Q=T{^W/^T} PUTTING THE VALUE EQI {1} ^E+W=T^W/^T [GIBBS HELMHOLT EQUATION]
Let X(t) be an iid random process and hence X(t) has an identical distribution for any t i.e., distributions are identical at instants of time t1, t2...tn, so 1st order pdfs f(x1;t1), f(x2;t2)....f(xn;tn) are time invariant and further X(t1) and X(t2) are independent for any two different t1 and t2. So, f(x1, x2, . . . , xn; t1, t2, . . . , tn) = f(x1;t1)*f(x2;t2)*....*f(xn;tn) f(x1;t1), f(x2;t2).... f(xn;tn) are time invariant, therefore their product f(x1, x2, . . . , xn; t1, t2, . . . , tn) is also time invariant which is nth order pdf. So X(t) is strict sense stationary.