answersLogoWhite

0

-t/(t-1)^2+1/(t-1)

User Avatar

Wiki User

13y ago

What else can I help you with?

Related Questions

Derivative of x to the power -t?

well if you're finding the derivative with respect to x, it would be -tx^(-t-1)


What P1v1 divided by t1p2v2 divided by t2 solve for t1?

This question refers to the combined gas law: (P1V1)/T1=(P2V2)/T2, where P is pressure, V is volume, and T is temperature in Kelvins.To solve for T1, rearrange the equation to isolate T1.T1=(P1V1T2)/(P2V2)


What is the derivative of t?

If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"


Is the derivative of u with respect to v constant when t is held constant?

No, the derivative of u with respect to v is not constant when t is held constant.


What is the difference between internet t-1 and t-3?

A T1 is 1.5Mbps. A T3 or DS3 is 45 Mbps. THere are 28 T1's in a DS3. T1 Internet Services http://www.intelletrace.com/internet-services/T1-Internet-Service.html DS3 or T3 Internet Services http://www.intelletrace.com/internet-services/DS3-Internet-Services.html


What is the transmission rate of T1 or T 3?

T1 transmits at about 1550 kilo bits per second; T3 around 6500 kbps.


What is the Anti-derivative of 4et-sint?

4e^t+cos(t)


What is derivative of 9et?

Assume that the expression is: y = 9e^(t) Remember that the derivative of e^(t) with respect to t is e^(t). If we take the derivative of the function y, we have.. dy/dt = 9 d[e^(t)]/dt = 9e^(t) Note that I factor out the constant 9. If we keep the 9 in the brackets, then the solution doesn't make a difference.


What is derivative of cot t dt?

d/dt cot (t) dt = - cosec2(t)


Who are some good T1 providers?

Some good T1 providers are AT&T, BellSouth, CavTel, Cogent, New Edge Networks, Qwest and Tel West. All of these companies off high quality T1 services.


Prove that if vector A has constant magnitude then its derivative is perpendicular to vector A?

Suppose A is a vector with real components. A can be written as <f(t), g(t), h(t)>. Since the magnitude of A is constant we have f(t)*f(t) + g(t)*g(t) + h(t)*h(t) = c, where c is a non-negative real number. Take derivative of both sides of equation we get 2*f(t)*df(t)/dt + 2*g(t)*dg(t)/dt + 2*h(t)*dh(t)/dt = 0. Divide both sides by 2, we get f(t)*df(t)/dt + g(t)*dg(t)/dt + h(t)*dh(t)/dt = 0. Thus the dot product of A and its derivative is 0. This implies the angle between A and its derivative is Pi/2. Hence they are perpendicular.


Model paper of msc chemistry in ou?

^E+W=Q.....................1 Q2-Q1/Q2=T2-T1/T2.....................2 W=Q2-Q1 Given W/Q =T2-T1/T2 T2-T1=^T and Q=^W ^w/Q=^T/T Q=T{^W/^T} PUTTING THE VALUE EQI {1} ^E+W=T^W/^T [GIBBS HELMHOLT EQUATION]