-t/(t-1)^2+1/(t-1)
Options settle T1, which means the settlement occurs one business day after the trade date.
Credit Risk. Credit risk or default risk evolves from the possibility that one of the parties to a derivative contract will not satisfy its financial obligations under the derivative contract.
Yes.
the derivative market means the the price of particular product in the market is fluctuating time by time.
A derivative is a contract with financial performance that is derived from the performance of something else. That "something else" is an underlying asset commonly termed "the underlying" and may be another financial instrument, another derivative, or an index of some kind.
well if you're finding the derivative with respect to x, it would be -tx^(-t-1)
This question refers to the combined gas law: (P1V1)/T1=(P2V2)/T2, where P is pressure, V is volume, and T is temperature in Kelvins.To solve for T1, rearrange the equation to isolate T1.T1=(P1V1T2)/(P2V2)
If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"
No, the derivative of u with respect to v is not constant when t is held constant.
A T1 is 1.5Mbps. A T3 or DS3 is 45 Mbps. THere are 28 T1's in a DS3. T1 Internet Services http://www.intelletrace.com/internet-services/T1-Internet-Service.html DS3 or T3 Internet Services http://www.intelletrace.com/internet-services/DS3-Internet-Services.html
T1 transmits at about 1550 kilo bits per second; T3 around 6500 kbps.
4e^t+cos(t)
Assume that the expression is: y = 9e^(t) Remember that the derivative of e^(t) with respect to t is e^(t). If we take the derivative of the function y, we have.. dy/dt = 9 d[e^(t)]/dt = 9e^(t) Note that I factor out the constant 9. If we keep the 9 in the brackets, then the solution doesn't make a difference.
d/dt cot (t) dt = - cosec2(t)
Some good T1 providers are AT&T, BellSouth, CavTel, Cogent, New Edge Networks, Qwest and Tel West. All of these companies off high quality T1 services.
Suppose A is a vector with real components. A can be written as <f(t), g(t), h(t)>. Since the magnitude of A is constant we have f(t)*f(t) + g(t)*g(t) + h(t)*h(t) = c, where c is a non-negative real number. Take derivative of both sides of equation we get 2*f(t)*df(t)/dt + 2*g(t)*dg(t)/dt + 2*h(t)*dh(t)/dt = 0. Divide both sides by 2, we get f(t)*df(t)/dt + g(t)*dg(t)/dt + h(t)*dh(t)/dt = 0. Thus the dot product of A and its derivative is 0. This implies the angle between A and its derivative is Pi/2. Hence they are perpendicular.
^E+W=Q.....................1 Q2-Q1/Q2=T2-T1/T2.....................2 W=Q2-Q1 Given W/Q =T2-T1/T2 T2-T1=^T and Q=^W ^w/Q=^T/T Q=T{^W/^T} PUTTING THE VALUE EQI {1} ^E+W=T^W/^T [GIBBS HELMHOLT EQUATION]