Of course; the reaction is:
Ag+ + NO-3 + Na+ + Cl- = Na+ + NO-3 + AgCl
Silver chloride is a white precipitate, very insoluble in water.
(AgCl has Ksp = 1.8 x 10-10)-5.1 x 10-10
NaCl(aq) + AgNO3(aq) = AgCl(s) + NaNO3(aq) - so the precipitate is white silver chloride.
One mole of chloride (Cl-) to one mole of Ag+ ions: Cl- + Ag+ --> AgCl(s)
Four ions exist: Na+, Cl-, Ag+, (NO3)-; sodium chloride react with silver nitrate:NaCl + AgNO3 = AgCl + NaNO3AgCl is insoluble in water.
The net ionic equation for silver nitrate (AgNO3) and sodium chloride (NaCl) in water is: Ag^+ + Cl^- -> AgCl(s) This equation represents the formation of a white precipitate of silver chloride when silver ions react with chloride ions in the solution.
Ag^+ (aq) + SCN^- (aq) → AgSCN (s) This reaction forms a precipitate of silver thiocyanate, a white solid.
This yields a light sensitive AgCl precipitate the above answer is not possible since there is no Silver (Ag) in either HNO3 or NaCl
No, a solid does not form when NaCl and NaOH are combined in solution. NaCl dissociates into Na+ and Cl- ions in solution, while NaOH dissociates into Na+ and OH- ions. The ions remain dissolved in the solution and do not form a solid precipitate.
NaCl and HCl doesn't react.
NaCl and sucrose can be distinguished by their chemical compositions. NaCl is a salt composed of sodium and chloride ions, while sucrose is a disaccharide composed of glucose and fructose molecules. A simple chemical test using silver nitrate can confirm the presence of chloride ions in NaCl, while sucrose will not react with this test.
It actually reacts with AgCl to produce NaCl (which is soluble), and some Na3[Ag(S2O3)2]complexes which are also soluble in water.
NaCl (ag)