1.Weigh 58,44 g ultrapure NaCl dried at 110 0C for 30 min.
2. Transfer NaCl in a clean 1 L volumetric flask using a funnel. 3. Wash the funnel with 0,9 L demineralized water.
4. Put the flask in a thermostat and maintain 30 min at 20 0C.
5. Add demineralized water up to the mark.
6. Stir vigorously and transfer in a clean bottle with stopper.
7. Add a label with necessary information.
To make a 1M solution of sodium chloride in 1 liter of water, you would need 58.44 grams of sodium chloride. This is based on the molecular weight of sodium chloride, which is 58.44 g/mol.
sodium plus chlorine yields sodium chloride
Sodium chloride is used to prepare the 0,9 % isotonic solution.
Sodium chloride is the result of this reaction: NaOH + HCl = NaCl + H2O
Sodium hydroxide solution will be on the top.
Adding hydrochloric acid.
In a 1M solution of sodium chloride, there would be 1 mole of sodium ions and 1 mole of chloride ions in 1 liter of the solution. This is because each formula unit of sodium chloride dissociates into one sodium ion and one chloride ion in solution.
Sodium chloride is NaCl. Sulfuric acid is H2SO4.
The answer is 0,1648 g NaCl.
Chlorine gas. Cl2
Sodium is separated from sodium chloride by electrolysis.
The salt used to prepare a mummy is sodium carbonate not sodium chloride.