The density of salt s 2,165 g/cm3. The apparent density is of course lower.
If the density of table salt is 0.92 grams per ml, then there are approximately 4.5 grams of salt in one teaspoon, usually considered to be 5 ml.
the mass in 20 ml
Proportionally you will need 1 and 1/2 mg of salt.
To calculate the amount of salt needed to saturate 25 ml of water, we can use a proportion based on the solubility limit in 100 ml of water. Since 100 ml can dissolve 36 g of salt, 25 ml can dissolve 9 g of salt (25/100 * 36 = 9). Therefore, you would need to add 9 grams of salt to saturate the 25 ml of water.
1 pound of table salt, with a density of 1.02 g/mL, will equal about 1.88 US cups.
Does not convert; milligrams (mg) and grams (g) are measures of weight or mass and mL (milliliters) is a measure of volume.
This depends on the concentration of this salt water.
The difference in mass between two salt solutions of the same volume can be due to differences in the density of the salts dissolved in the solutions. If one salt is denser than the other, the solution containing the denser salt will have a greater mass for the same volume. Additionally, any impurities, solutes, or additives present in one solution but not the other can also contribute to differences in mass.
Hold on here, I need to do some heavy calculation ... okay, done. One tablespoon of table salt contains 1.0 tablespoons of sodium chloride. Since the atomic weight of sodium chloride is 58.5, 1 meq of salt is 58.5 mg. Since one tablespoon = 14.8 ml and salt weights 1.02 g/ml, one tablespoon of salt weighs 15.2 g or 15,200 mg. So one tablespoon of salt = 15,200 / 58.5 = 260 mEQ.
The density of the salt solution is 1.14 g/ml. This is calculated by dividing the mass (57.0 g) by the volume (50.0 ml).
Primarily, one gains weight because salt retains water. It's heavy and one becomes waterlogged.
Salt Water Density: 1.027 g/mL Fresh Water Density: 1 g/mL