55-88g
One walnut brownie from 7-11 has 88g of carbs.
C = 1 * 12.01 g = 12.01 g O = 2 * 16.00 g = 32.00 g CO2 = 44.01 g (12.01 g/44.01 g) * 100% = 27.289% 0.27 * 88 g = 23.76g Or more accurately.. 0.27289 * 88 g = 24.01 g There is about 24 grams of carbon in 88 grams of carbon dioxide.
To answer this question, we need more information--eighty-eight what is equal to 'x' number of kilograms.ounces? 88oz = 2.5kgpounds? 88lb = 39.9kggrams? 88g = 0.088kgtons? 88ton = 79 832.26kgmaybe I've managed to answer your question, if not, the original question needs to have more information
The solution is saturated at 20°C since 88g of sodium nitrate can dissolve in 100g of water. If you add an additional 10g of sodium nitrate, it will exceed the solubility limit at 20°C, causing the excess sodium nitrate to form a precipitate at the bottom of the solution.
There are 90g in a cup of white all purpose flour. There are 90g in a cup of white all purpose flour. It depends on what type of flour it is. In all purpose gold medal flour there are only 88g of carbs in 1 cup of flour ( 22g per 1/4 cup ).
No, the 88g cartridge is much larger than it's 12g counterpart and will not fit the same applications. Also, the 88g AirSource cartridge has a threaded neck and screws into place, whereas the 12g powerlet is clamped in place.
Sodium nitrate is soluble in water at various temperatures. At 0°C, approximately 88g of sodium nitrate can dissolve in 100ml of water. As the temperature increases, the solubility of sodium nitrate in water also increases.
1.75 mole CHCl3 (6.02 X 10^23 mole CHCl3) = 1.05 X 1024 atoms of CHCl3 ====================
fruit and veg - 400g/5 portions a day. 34g of breakfast cereals a day. double white fish from 44g to 88g a week. 1/3 the salt you are eating. child reduce sugar intake by 1/2, adults stay the same.
Assuming this is the reaction: FeS + H2 --> H2S + Fe, the molar mass of H2S is 34g/mol, so you have about 4.4mol of it. Because the equation features reagents in a 1:1 ratio, this means you will require 4.4mol of FeS. FeS has a molar mass of 88g/mol, and 88x4.4=387.2g FeS required.
The mass percent of a saturated solution of NaNO3 at 20°C can be calculated by dividing the mass of NaNO3 in the saturated solution (82 g) by the total mass of the solution (82 g NaNO3 + 100 g water) and then multiplying by 100%. This results in a mass percent of 82/182 * 100% ≈ 45.1%.