The answer is 51,7 mmoles.
4 milliequivalents of sodium chloride solution is a solution having 0,2338 g in 1 L.
Normal saline (0.9% NaCl) has a concentration of 154 milliequivalents per liter of sodium. This means that a 1L bag of normal saline would contain 154 milliequivalents of sodium.
To calculate the milliequivalents of chloride ions in 0.725 grams of chloride, you first need to determine the molar mass of chloride (Cl⁻) which is 35.45 g/mol. Next, calculate the number of moles in 0.725 grams by dividing the mass by the molar mass. Then, convert moles to milliequivalents by multiplying by 1000 (since 1 mole of ions = 1000 milliequivalents).
1 mg of sodium is equivalent to approximately 0.0435 milliequivalents (mEq) of sodium.
Sodium chloride is soluble in water.
It depends on the concentration of sodium chloride.
There are two elements that make up sodium chloride. They are sodium and chlorine.
The chemical name "sodium chloride" has two parts: "sodium" and "chloride." "Sodium" refers to the cation (positively charged ion) in the compound, while "chloride" refers to the anion (negatively charged ion).
This depends on the amount of sodium chloride.
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There are approximately 1,292 mg of chloride in 1 teaspoon of table salt. Converting this to milliequivalents (mEq), which takes into account the valence of the chloride ion, gives about 28.9 mEq of chloride in 1 teaspoon of salt.
The answer is 1,105 g.