120 mg of salt is equivalent to 0.12 grams. To put it into perspective, this amount is roughly 1/20th of a teaspoon of table salt, which typically weighs about 6 grams per teaspoon. Thus, 120 mg represents a very small quantity of salt.
On Earth, 1000 mg.
200 mg.
2608 mg of salt is 1500 mg of sodium i.e. half a teaspoon
120 mg = 0.12 g
0,8 g is 800 mg.
120 mg = 0.12 g
120 g = 120000 mg. 1 g = 1000 mg
1000 mg = 1 gram so 120 mg = 120/1000 = 0.12 gr.
480ml
There are 0.120 g in 120 mg. 1 g = 1000 mg 1 mg = 0.001 g
1,000 mg = 1.000 g 100 mg = 0.100 g 120 mg = 0.120 g
this question is not hard to answer, but it does require that one make some assumptions. The simplest answer assumes that the 20% salt solution refers to per cent by mass. Thus: a 20% salt solution is one which contains 20 mg salt for every 100 mg solution where the solution consists of a mixture of 20 mg salt plus 80 mg water. A 35% salt solution would contain 35 mg salt for every 65 mg water. Now, assuming that all the water in 18 mg of a 20% salt solution remains in the final solution we see that 18 mg salt solution x 20 mg salt/100 mg salt solution gives 3.6 mg of salt; thus, there are 18 mg total solution - 3.6 mg salt = 14.4 mg water. So the final salt solution must be one that contains 14.4 mg water and enough salt to make it 35% salt by mass. Mathematically, this is written as Z mg salt/(Z mg + 14.4 mg water) = 35/100 This gives Z = 0.35*(Z + 14.4) or Z = 0.35*Z + 0.35*14.4 which is same as Z = 0.35*Z + 5.04 and 0.65*Z = 5.04 so Z = 5.04/0.65 = 7.75 mg total salt needed. We started with 3.6 mg salt, so we must add 7.75 -3.6 = 4.15 mg salt Check: 7.75 mg salt/(7.75 mg salt + 14.4 mg water) = 0.35 or 35% There you go! --assuming that much salt dissolves that amount of water!