96
The mean average of a set of numbers is the sum of the numbers divided by how many of them there are. If there are 8 numbers with a sum of 2464, their mean average is 2464 ÷ 8 = 308.
8 10 12 14 16
The average of a sequence of numbers is equal to Average(x1, ... , xi) = Sum(n, i = 1)[xi]/n Example: Find the average of 5, 6, 8, 12, 15, and 29. Average = Sum[5, 6, 8, 12, 15, 29]/6 Average = (5+6+8+12+15+29)/6 Average = 11
To find the average of all seven numbers, we can use the formula for the average: (sum of all numbers) / (total number of numbers). Given that the average of the first four numbers is 15, the sum of the first four numbers is 15 * 4 = 60. Similarly, the sum of the last three numbers is 8 * 3 = 24. Therefore, the sum of all seven numbers is 60 + 24 = 84. Finally, the average of all seven numbers is 84 / 7 = 12.
6 and 2 are a number pair with a sum of 8 and a product of 12
10 + 2 = 12 10 - 2 = 8
the sum of two numbers is
4 and 12
The sum of 8 and 4 is 12. In mathematics, addition is the operation of combining two or more numbers to find their total. In this case, when you add 8 and 4 together, you get the sum of 12.
2 and 6 have.
To find the average of a set of numbers, you add all the numbers together and then divide by the total number of values. In this case, the sum of 8, 9, 10, 11, and 12 is 50. To find the average, you divide 50 by the total number of values, which is 5. Therefore, the average of 8, 9, 10, 11, and 12 is 10.
12 and 8