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E1, E2, E3, E4, and E5

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What five numbers have a median of 12 a mode of 10 and mean of 12?

Assuming by "numbers" you mean "whole numbers":{10, 10, 12, 13, 15}If the five numbers are {a, b, c, d, e} with a &le; b &le; c &le; d &le; e, then:median = 12 &rarr; c = 12leaving only two numbers (a, b) &le; 12.mode = 10 &rarr; two or more numbers equal 10 (which is less than 12) &rarr; a = b = 10The final two numbers (d, e) are not equal, both greater than 12, and such that the sum of all five numbers is 60.10 + 10 + 12 + d + e = 60 &rarr; d + e = 28 &rarr; d = 13, e = 15&rarr; {a, b, c, d, e} = {10, 10, 12, 13, 15}[If "numbers" includes "decimal numbers" (ie numbers with a fractional part), then as long as d + e = 28 and 12 < d < e there are infinitely many solutions, eg {10, 10, 12, 12.5, 15.5}, {10, 10, 12, 13.75, 14.25}]


How do you write a c program to get the average of five numbers?

If the five numbers need to be read from command-line, you'll have to parse the arguments (the function atoi() will come in handy there). If the five numbers are known at compile-time, you'll get a program like below: #include &lt;stdio.h&gt; int main(int argc, char **argv) { int a = 10; int b = 20; int c = 30; int d = 40; int e = 50; int result = (a + b + c + d + e) / 5; printf("The average of %d, %d, %d, %d and %d is %d\n", a, b, c, d, e, result); }