You just dissolve some solid sodium chloride in water and make it up to a 1 molar solution.
for example if you wanted one litre of solution you'd dissolve one mole of NaCl in 1 litre
1 mole = 23 + 35.5 = 58.5grams approximately
you'll have to look it up for more accurate gram molecular masses
A 0.0% NaCl solution is a solution with absolutely no NaCl.
The concentration of NaCl in a solution that contains 0.9 NaCl is 0.9 grams of NaCl per 100 grams of solution.
a) In a solid state, NaCl is an insulator since the ions are held in fixed positions and cannot move to conduct electricity. b) When NaCl is melted into a liquid state, the ions are free to move and can carry an electric current, making molten NaCl an electrical conductor. c) In an aqueous solution of NaCl, the salt dissociates into ions, allowing them to move freely in the solution and carry an electric current, making it a good conductor of electricity.
If 10 is 10 molar for you, this is a saturated solution of NaCl.
A 1M NaCl solution is more hypertonic than a 1M sucrose solution. This is because NaCl dissociates into two ions (Na⁺ and Cl⁻) in solution, effectively doubling the concentration of solute particles compared to the non-dissociating sucrose. Therefore, the osmotic pressure of the NaCl solution is higher, making it more hypertonic.
Adding NaCl solution to soap mixture helps to precipitate out the soap, making it easier to separate from the rest of the solution. This process is known as salting out and helps concentrate the soap for further processing.
Sodium chloride is a salt; the water solution is neutral.
Yes, because the solution of NaCl is an electrolyte.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
Pure solide NaCl is not electrically conductive. The water solution of NaCl is an electrolyte and is conductive.
The pH of a solution containing NaCl is neutral, around 7.
To determine the amount of NaCl in the solution, you first need to calculate the moles of NaCl present. Using the given molarity (2.48 M) and the volume of the solution (assumed to be 806 g = 806 ml for water), you can find the moles of NaCl. Then, you convert the moles of NaCl to grams using the molar mass of NaCl (58.44 g/mol) to find the amount of NaCl in the solution.