Sulfuric acid and table salt. Reacting them will produce hydrogen chloride (gas) and sodium sulfate by the Mannheim process (see link below):
2NaCl(s) + H2SO4(l) --> 2HCl(g) + Na2SO4(s)
Other reactions are possible--for instance, sodium bisulfate (NaHSO4(s)) can also be expected to be produced at lower temperatures than the Mannheim process requires.
Mixing aqueous solutions of NaCl and H2SO4 will yield no net reaction because the driver for the reaction is the liberation of free HCl gas. In the presence of excess water, the HCl that would have been liberated, instead, forms hydrochloric acid and remains ionized and in solution up to a concentration of around 37% at STP.
The answer is: any reaction.
To completely neutralize 100ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so it will require 2 moles of NaCl to neutralize 1 mole of H2SO4. Therefore, you would need 2 moles of NaCl for every mole of H2SO4. With a 1M solution of H2SO4 in 100ml, you have 0.1 moles of H2SO4. Therefore, you would need 0.2 moles of NaCl. The molar mass of NaCl is approximately 58.44g/mol, so you would need approximately 11.7 grams of NaCl to completely neutralize the 1M H2SO4 solution.
NaCl(s) + C2H5OH(l) --> NaOH(aq) + C2H5Cl(aq)
Nothing happens. NaCl is virtually insoluble in acetone. Only 0.042 mg of NaCl will dissolve in 100 g of acetone at 25°C.
NaCl H2SO4 KNO3 CaCl3
NaCl doesn't neutralize sulfuric acid.
To completely neutralize 100 ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so you need 2 moles of NaCl for each mole of H2SO4. Therefore, you would need 2 moles of NaCl, which is equal to 117 grams (2 x molar mass of NaCl) to neutralize 100 ml of 1M H2SO4.
NaCl and H2SO4 doesn't react.
2NaCl + H2SO4 ----> 2HCl + Na2SO4 *molar mass of H2SO4 is 98.09g *molar mass of NaCl is 58.44g *molar mass HCl is is 36.46g Moles NaCl = 150 g / 58.44 = 2.56 The ratio between NaCl and H2SO4 is 2 : 1 so NaCl is the limiting reactant We would get 2.56 mol HCl => 2.56 mol x 36.46 g/mol = 93.3 g
There is no reaction for this process.H2SO4 + NaCl => N.R.
No, they are immiscible.
NaCl doesn't react with KNO3.NaCl + AgNO3 = NaNO3 + AgCl(s)NaOH + HCl = NaCl + H2ONa2CO3 + 2 HCl = 2NaCl + CO2 + H2OBaCl2 + H2SO4 = BaSO4(s) + 2 HClCuSO4 and Zn(NO3)2 doesn't react.