A cone has one vertex and one edge.
A cone has one vertex, one edge, and one base.
triangle
one face one vertex and two circle edges * * * * * What kind of cone is that? It has 1 edge, 2 faces (one curved and one plane), and 1 vertex.
The solid that has one flat face, one curved face, one edge, and one vertex is a cone. The flat face is the circular base, the curved face is the conical surface, the edge is the circular boundary where the base meets the curved surface, and the vertex is the pointed tip of the cone.
import java.util.List; import java.util.ArrayList; import java.util.Collections; class Vertex implements Comparable<Vertex> { public final String name; public Edge[] adjacencies; public double minDistance = Double.POSITIVE_INFINITY; public Vertex previous; public Vertex(String argName) { name = argName; } public String toString() { return name; } public int compareTo(Vertex other) { return Double.compare(minDistance, other.minDistance); } } class Edge { public final Vertex target; public final double weight; public Edge(Vertex argTarget, double argWeight) { target = argTarget; weight = argWeight; } } public class Dijkstra { public static void computePaths(Vertex source) { source.minDistance = 0.; PriorityQueue<Vertex> vertexQueue = new PriorityQueue<Vertex>(); vertexQueue.add(source); while (!vertexQueue.isEmpty()) { Vertex u = vertexQueue.poll(); // Visit each edge exiting u for (Edge e : u.adjacencies) { Vertex v = e.target; double weight = e.weight; double distanceThroughU = u.minDistance + weight; if (distanceThroughU < v.minDistance) { vertexQueue.remove(v); v.minDistance = distanceThroughU ; v.previous = u; vertexQueue.add(v); } } } } public static List<Vertex> getShortestPathTo(Vertex target) { List<Vertex> path = new ArrayList<Vertex>(); for (Vertex vertex = target; vertex != null; vertex = vertex.previous) path.add(vertex); Collections.reverse(path); return path; } public static void main(String[] args) { Vertex v0 = new Vertex("Harrisburg"); Vertex v1 = new Vertex("Baltimore"); Vertex v2 = new Vertex("Washington"); Vertex v3 = new Vertex("Philadelphia"); Vertex v4 = new Vertex("Binghamton"); Vertex v5 = new Vertex("Allentown"); Vertex v6 = new Vertex("New York"); v0.adjacencies = new Edge[]{ new Edge(v1, 79.83), new Edge(v5, 81.15) }; v1.adjacencies = new Edge[]{ new Edge(v0, 79.75), new Edge(v2, 39.42), new Edge(v3, 103.00) }; v2.adjacencies = new Edge[]{ new Edge(v1, 38.65) }; v3.adjacencies = new Edge[]{ new Edge(v1, 102.53), new Edge(v5, 61.44), new Edge(v6, 96.79) }; v4.adjacencies = new Edge[]{ new Edge(v5, 133.04) }; v5.adjacencies = new Edge[]{ new Edge(v0, 81.77), new Edge(v3, 62.05), new Edge(v4, 134.47), new Edge(v6, 91.63) }; v6.adjacencies = new Edge[]{ new Edge(v3, 97.24), new Edge(v5, 87.94) }; Vertex[] vertices = { v0, v1, v2, v3, v4, v5, v6 }; computePaths(v0); for (Vertex v : vertices) { System.out.println("Distance to " + v + ": " + v.minDistance); List<Vertex> path = getShortestPathTo(v); System.out.println("Path: " + path); } } }
It has 1 edge, 2 faces (one curved and one plane), and 1 vertex.It has 1 edge, 2 faces (one curved and one plane), and 1 vertex.It has 1 edge, 2 faces (one curved and one plane), and 1 vertex.It has 1 edge, 2 faces (one curved and one plane), and 1 vertex.
vertex vertex
A cycle is a closed path such that the end vertex of the final edge is the start vertex of the first edge.
How about a sphere as an example that fits the given description
No but it has a circular edge
vertex