2M NaCl is a equivalent to a solution with 116,88 g NaCl in 1 L water.
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
Two moles of sodium chloride is equivalent to 116,88 (rounded) g.The molar mass of NaCl 58.5 grams per mole. 117 grams of salt is equivalent to two moles. Dissolve this much of salt in exactly 1L of distilled water in a volumetric flask to prepare 2M NaCl.
Adding NaCl solution to soap mixture helps to precipitate out the soap, making it easier to separate from the rest of the solution. This process is known as salting out and helps concentrate the soap for further processing.
30 percent of 2m = 0.6m30% of 2m= 30% * 2m= 30%/100% * 2m= 6/10m or 0.6m
2m is 200cm..
To completely neutralize 100ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so it will require 2 moles of NaCl to neutralize 1 mole of H2SO4. Therefore, you would need 2 moles of NaCl for every mole of H2SO4. With a 1M solution of H2SO4 in 100ml, you have 0.1 moles of H2SO4. Therefore, you would need 0.2 moles of NaCl. The molar mass of NaCl is approximately 58.44g/mol, so you would need approximately 11.7 grams of NaCl to completely neutralize the 1M H2SO4 solution.
It is: 2m times 2m is equivalent to 4m^2
2m is 2000cm
275cm is greater than 2m
2m = 26m = 26/2m = 13
7m-2m = 5