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The molarity of a 10.0 L aqueous solution that contains 23.4 grams of sodium chloride is?
The first step is to convert the mass of sodium chloride to moles using its molar mass. Then, divide the moles of sodium chloride by the volume of the solution in liters to calculate the molarity.
What is the molarity of 6.2L of solution if it contains 2.5 moles if sodium chloride?
Molarity means moles per litre. You have to bring the ratio to moles per a litre. So, 2.5 divided by 6.2 is 0.403 molar.
A solution contains 11 by mass of sodium chloride This means that?
100 g of the solution contains 11 g of sodium chloride
What is the molarity of a 4.625 L solution that is made from 21.26 g of Sodium chloride?
In this case the molarity is 0,079 mol/L.
How many moles of sodium ions and chloride ions are present in 1 liter of a 1M solution of sodium chloride?
In a 1M solution of sodium chloride, there would be 1 mole of sodium ions and 1 mole of chloride ions in 1 liter of the solution. This is because each formula unit of sodium chloride dissociates into one sodium ion and one chloride ion in solution.
What is the molarity of 6.2 L of solution if it contains 2.5 moles of sodium cholride?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, you have 2.5 moles of sodium chloride in 6.2 L of solution. Thus, the molarity is 2.5 moles / 6.2 L = 0.40 M.
What is the molarity of 250cm3 sodium chloride solution containing 2 moles?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, there are 2 moles of sodium chloride in 250 cm^3, which is equivalent to 0.25 L. Therefore, the molarity of the solution is 8 M (2 moles / 0.25 L).
What is the difference between Sodium chloride and ammonium chloride solutions?
Sodium chloride (NaCl) is a compound made of sodium and chloride ions, while ammonium chloride (NH4Cl) is a compound made of ammonium and chloride ions. In solution, sodium chloride dissociates into Na+ and Cl- ions, which are both spectator ions. Ammonium chloride, on the other hand, dissociates into NH4+ and Cl- ions, with the NH4+ ion acting as a weak acid in solution. This difference in ion composition and behavior affects the properties and reactions of the two solutions.
How many moles of sodium chloride are in 5.08 L of a 2.36 M solution?
To find the number of moles of sodium chloride, you can multiply the volume of the solution by its molarity. moles = volume (L) * molarity moles = 5.08 L * 2.36 mol/L moles = 11.9928 mol Therefore, there are approximately 11.99 moles of sodium chloride in 5.08 L of a 2.36 M solution.
What is the molarity when water is added to 2 moles of sodium chloride to make 0.5 liter of solution?
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
What forms an electrolyte solution?
Salt in water is sodium. Ringer's lactate solution (sodium lactate solution and Hartmann's solution), is a mix of sodium chloride, sodium lactate, potassium chloride, and calcium chloride in water. Sodium Chloride is a mix of sodium and chloride.
How many mols of NaCl are present in 1 liter of a 0.1M solution of sodium chloride?
There would be 0.1 moles of NaCl present in 1 liter of a 0.1M solution of sodium chloride. This is based on the definition of molarity which is moles of solute per liter of solution.
