Sodium chloride is soluble only in the water solution of HCl.
HCl is the chemical formula of hydrochloric acid. NaCl is the chemical formula of sodium chloride.
NaCl and HCl doesn't react.
When hydrochloric acid (HCl) and sodium hydroxide (NaOH) are combined in water, they react to form water (H2O) and sodium chloride (NaCl), which is table salt. The reaction is exothermic, meaning it releases heat. The equation for this neutralization reaction is: HCl + NaOH -> NaCl + H2O.
Soluble ionic compounds like NaCl, and some covalent compounds like HCl(g) which will dissociate in water.
NaCl
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
NaOH(hydroxide) + HCl(acid) ---------> NaCl(salt) + H2O(water)
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
The reaction between NaOH and HCl produces NaCl (sodium chloride) and H2O (water). The balanced chemical equation is: NaOH + HCl → NaCl + H2O.
HCl + NaOH --> NaCl + H2O is balanced as you wrote it.But, since sodium is always soluble in water at temperatures below the boiling point of the solution, the net ionic equation for the reaction at temperatures lower than the boiling point would actually be: HCl + OH- --> Cl- + H2OOr, if the hydrochloric acid was already in solution, then simplyH+ + OH- ---> H2O
NaOH + HCl >> NaCl + H2O
NaCl is not soluble in acetone.