Sodium chloride is soluble only in the water solution of HCl.
HCl is the chemical formula of hydrochloric acid. NaCl is the chemical formula of sodium chloride.
NaCl and HCl doesn't react.
When hydrochloric acid (HCl) and sodium hydroxide (NaOH) are combined in water, they react to form water (H2O) and sodium chloride (NaCl), which is table salt. The reaction is exothermic, meaning it releases heat. The equation for this neutralization reaction is: HCl + NaOH -> NaCl + H2O.
Soluble ionic compounds like NaCl, and some covalent compounds like HCl(g) which will dissociate in water.
NaCl
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
NaOH(hydroxide) + HCl(acid) ---------> NaCl(salt) + H2O(water)
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
The reaction between NaOH and HCl produces NaCl (sodium chloride) and H2O (water). The balanced chemical equation is: NaOH + HCl → NaCl + H2O.
NaCl is not soluble in acetone.
NaOH + HCl >> NaCl + H2O
No, 2-naphthol is not soluble in hydrochloric acid (HCl) because it is a nonpolar compound and HCl is a polar solvent.