Sodium chloride may be used as standard (for example to prepare sodium solutions with known concentration) because is a stable compound.
The mass of silver nitrate is 30,6 g.
You need 145,337 g silver nitrate.
Sodium chloride is needed to precipitate soap from solutions.
To prepare a 40.0% lithium nitrate solution, 60mL of the solution would be solvent (water) and 90mL would be solute (lithium nitrate). Therefore, you would need 90mL of lithium nitrate to prepare 150mL of the 40.0% solution.
To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.
The evidence obtained from the silver nitrate tests strongly suggests that the residue is likely potassium chloride. The formation of a white precipitate in the silver nitrate tests is characteristic of chloride ions reacting with silver ions. However, further confirmatory tests may be needed to conclusively prove the identity of the residue as potassium chloride.
It depends on the volume, if we consider 1 liter of the solution 500 mg of sodium chloride is needed.
There is no chemical reaction between sod chloride solution and water, it would just dilute the sod chloride solution.
The sodium chloride mass needed is 292,2 g
To prepare 4N potassium chloride solution, dissolve 149.5 g of potassium chloride in 1 liter of water. This will give you a solution with a concentration of 4N. Make sure to use a balance to accurately measure the amount of potassium chloride needed.
The saturated solution of sodium chloride is 379,3 g for 1 kg solution at 8o oC.
Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.