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Is you were born in 311 bc and died in 2ad would you be 631 years old?

As there was no year zero, you would be 312 years old.


Factor this expression check by multiplying factors.4ac plus 2ad plus 2bc plus 4bd?

ac + 2ad + 2bc + 4bd = a(c + 2d) + 2b(c + 2d) = (a + 2b)(c + 2d) Now expand to confirm your answer: c(a + 2b) + 2d(a + 2b) = ac + 2bc + 2ad + 4bd ≡ ac + 2ad + 2bc + 4bd


How many years were there between 5 BC and 5 AD?

All of each of 5BC, 4BC, 3BC, 2BC, 1BC, 1AD, 2AD, 3AD, 4AD, so 9 Or, you might mean 4BC ........... 4AD so 8


Factoring by grouping ac plus 2ad plus 2bc plus 4bd?

ac + 2ad + 2bc + 4bd (ac + 2ad) + (2bc + 4bd) group the figures a(c + 2d) + 2b(c + 2d) remove the common divisors of each set (a + 2b)(c + 2d) take the figures in parentheses as one set, and add the outside figures as the other


How many earth years is it year?

About 284 years is one pluto year!


What does 4ac 2ad 2bc bd factor into?

(2a + b)(2c + d)


Leap year is every how many years?

every 4 years


How many years ago was the year 1452?

558 years ago.


What is the formula of vertical velocity?

vf=vi+at or vf2=vi2+2ad where a=-9.8m/s2


Who created the first model of planetary motion?

Ptolemy created the Geocentric model in 2AD


Factor this expression 4ac plus 2ad plus 2bc plus bd?

4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)


What is the correct formula manipulation to find acceleration when using the equation vf2 vi2 2ad?

To find acceleration using the equation vf^2 = vi^2 + 2ad, you can rearrange the formula to isolate 'a'. First, subtract vi^2 from both sides to get vf^2 - vi^2 = 2ad. Then, divide both sides by 2d to solve for acceleration: a = (vf^2 - vi^2) / (2d).