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What else can I help you with?
How do sailors say yes?
Most sailors say 'aye' for 'yes'
What is the birth name of Chinkee Tan?
Chinkee Tan's birth name is Ferdinand Tan.
What is the birth name of Yce Tan?
Yce Tan's birth name is Rycelonia Tan.
When did Liverpool Sailors' Home end?
Liverpool Sailors' Home ended in 1969.
What is a collection of sailors called?
A collection of sailors is called a crew of sailors.
What is the collective noun for hundreds of sailors?
The collective noun for 'sailors' is a crew of sailors, whether there are two sailors or hundreds of sailors.
What is the word for a group of sailors?
crew
What is the possessive of sailors?
sailors'
What did sailors do in 1700?
oKay this question is very good. the poor sailors usally had no choise to be a sailor.At sea the got,terrible illnesses such as fevers,of course they ate mostly sea food. Punisments are much worse tan school. They got whipped,punched,smacked and if they where really bad they got drowned or their limbs got cut of.
Tan 9 plus tan 81 -tan 27-tan 63?
tan(9) + tan(81) - tan(27) - tan(63) = 4
Men and women who work on ship are called?
Crew
What do you call a what of sailors?
A crew of sailors.
What is a antonym of pale?
Tan Tan
Is sailors plural possessive noun?
Sailors
What is the collective noun for sailors on an airship?
Sailors on any type of vessel are called a crew of sailors.
In this story, Rainsford does not have a conflict with?
the ship captain and sailors the ship captain and sailors
If for a triangle abc tan a-b plus tan b-c plus tan c-a equals 0 then what can you say about the triangle?
tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).
