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The reaction between potassium iodide (KI) and lead(II) nitrate (Pb(NO₃)₂) results in the formation of lead(II) iodide (PbI₂) as a precipitate and potassium nitrate (KNO₃) in solution. The balanced chemical equation for this double displacement reaction is:
2 KI + Pb(NO₃)₂ → PbI₂ (s) + 2 KNO₃.
Lead(II) iodide appears as a bright yellow solid.
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What is KI plus Cl2?
The reaction is:Cl2 + 2 Ki = 2 KCl + I2
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KI or potassium iodide will be basic in solution because it is the product of KOH (a strong base) and HI (a weak acid.)
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The product is(the product of the first term of each)plus(the product of the last term of each) plus(the product of the first term of the first and the last term of the second) plus(the product of the first term of the second and the last term of the first).
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What is the product of (x plus 4) (x plus 4)?
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Balance hi plus koh equals ki plus h2o?
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
What is the balanced chemical equation for KI plus Cl2 equals KCl plus I2?
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
What is product cycle of colorplus?
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