For a J-K flip-flop to set the output Q upon the active clock transition (typically the rising edge), the conditions are that the J input must be high (J = 1) and the K input must be low (K = 0). This combination ensures that when the clock triggers, the flip-flop will set Q to 1. If both J and K are low, or if J is low and K is high, the output Q will either remain in its current state or reset, respectively.
Unfortunately you cannot input card codes into Yu-Gi-Oh 5D's Wheelie Breaker.
Input a code into the matrix.
wetvet escrgo
There is no cheat menu.
Via Action Replay...
An internal transition is a type of transition within a state in a finite state machine where there is a change in the state without any change in the input. It is used to represent actions or behaviors that occur without input triggering the transition.
'Active high input' refers to a signal or input condition that is considered "active" or "on" when the voltage level is high, typically close to the supply voltage. This means that when the input receives a high voltage, it triggers a response in the connected circuit or device. Conversely, 'active low input' signifies that the input is active when the voltage is low, usually close to ground level. In this case, a low voltage level triggers the response.
Excitation tables helps to know the input conditions of the flip flops that will cause the required transition from the present state to the next state.
In pneumatics, an AND circuit requires all input signals to be active for the output to be activated, meaning multiple conditions must be met simultaneously. Conversely, an OR circuit activates the output if at least one input signal is active, allowing for more flexibility in triggering the output. Essentially, AND circuits ensure that all conditions are satisfied, while OR circuits provide an alternative path for activation.
A LOW-ACTIVE gate input means that the gate's output is activated or enabled when the input signal is at a low voltage level (typically near 0 volts). In digital logic circuits, this characteristic is often seen in components like NAND and NOR gates. For example, a LOW-ACTIVE NAND gate will produce a high output unless all its inputs are low, while a LOW-ACTIVE NOR gate will produce a high output only when all its inputs are low. This behavior is essential for designing logic circuits that respond to specific input conditions.
Osmosis is the diffusion of water across a membrane, and does not require the input of energy. Active transport requires energy input.
The energy graph that represents the nonspontaneous transition is the one that shows an increase in energy over time, indicating that energy input is required for the transition to occur.
Active transport requires some form of energy input, usually ATP
The term "active low" means that the input on an IC requires a logic low for it to be activated, i.e a low voltage (of course the voltage range is dependent on the technology, TTL, CMOS etc) Active high is the opposite... the input requires a logic high for it to be activated. A simple example to illustrate, an 8bit counter can count UP/DOWN this functionality is controlled with only one pin, an active high on that pin to count up or low to count down.
In a spreadsheet application, it is the cell that has focus and that input can be made. The cell with the bold boundary is the active cell.
ATP
Passive processes do not require energy input and occur spontaneously, such as diffusion, osmosis, and facilitated diffusion. Active processes require energy input to proceed, such as active transport, endocytosis, and exocytosis to move substances against their concentration gradient.