114k
kenneth cornelius
-273.15 C
I think you might have wanted to tell us a little more information. It may be of use to know that absolute zero, 0 K = -273 C; the freezing point of water 0 C =273 K, and the boiling point of water, 100 C = 373 K
0 ºC = 273 K
4.44 C 277.59 K 3.56 Re
-108
A number , B , increased by P percent gives C where:C = ( B ) [ ( 100 + P ) / ( 100 ) ]C = ( 114 ) [( 100 + 20 ) / ( 100 ) ] = ( 114 ) [ 1.20 ]C = 136.8
Chalk. C-L-I-C-K C-L-O-C-K C-L-U-C-K C-H-U-C-K C-H-I-C-K Croak Crack Crook Creek
114 F = 45.56 CConversion formula: [°C] = ([°F] − 32) * 5 ⁄ 9 = (114 - 32) * 5 / 9 = 45.5 °C
71.25% C
#include<iostream.h> #include<conio.h> void main() { clrscr(); int i,k,a[10],c[10],n,l; cout<<"Enter the no. of elements\t"; cin>>n; cout<<"\nEnter the sorted elments for optimal merge pattern"; for(i=0;i<n;i++) { cout<<"\t"; cin>>a[i]; } i=0;k=0; c[k]=a[i]+a[i+1]; i=2; while(i<n) { k++; if((c[k-1]+a[i])<=(a[i]+a[i+1])) { c[k]=c[k-1]+a[i]; } else { c[k]=a[i]+a[i+1]; i=i+2; while(i<n) { k++; if((c[k-1]+a[i])<=(c[k-2]+a[i])) { c[k]=c[k-1]+a[i]; } else { c[k]=c[k-2]+a[i]; }i++; } }i++; } k++; c[k]=c[k-1]+c[k-2]; cout<<"\n\nThe optimal sum are as follows......\n\n"; for(k=0;k<n-1;k++) { cout<<c[k]<<"\t"; } l=0; for(k=0;k<n-1;k++) { l=l+c[k]; } cout<<"\n\n The external path length is ......"<<l; getch(); }
n-butane : Melting point −138.4 °C (135.4 K), boiling at −0.5 °C (272.6 K)iso-butane (methylpropane): Melting point -159.6 °C, (114 K) , boiling at -11.7 °C, (261 K)
K to C Formula: C = K - 273.15 C to K Formula: K = C + 273.15
Celsius to Kelvin: K = °C + 273.15 Kelvin to Celsius: °C = K - 273.15
about 114 k a year
Use this formula: K = (C + 273.15)C to K Formula: K = C + 273.15
The correct formula for converting from kelvins to degrees Celsius is C = K - 273. So, to convert 95 K to degrees Celsius, you would do C = 95 - 273 = -178 degrees Celsius.