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17y ago

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What is the average force on a 75 kg crash test dummy that crashes into a wall at 25 m per s and is brought to rest in 1s?

Let's use a combination of two equations F= ma and v= u + at where F= Force; m= mass; a= acceleration; v = final velocity= 0 m/s; u= initial velocity=25 m/s and t= time. From the equation v= u + at, we can solve for a. So, a = (v-u)/ t. Using F= ma F= m((v- u)/t)) F= 75kg((0-25 m/s)/ ls) F= (75 x 25) kg m/s^2 F= 1875 kg m/s^2= 1875 N


For how long should a force of 100 N act on a body of 20 kg so that it acquires a velocity of 200 ms?

u= 0 m/s v= 200 m/s m= 20 kg F= 100 N F= (mv - mu)/t 100 = (20*200 - 20*0)/t 100 = 4000/t t= 4000/100 t= 40 s hope it helps cheers ^_^


How would you calculate acceleration?

Acceleration is defined as the change in velocity, divided by the time it takes to achieve this change. There are also some other formulas which you can use, depending on what you know about a specific situation.


If the speeding train hits the brakes and it takes the train 39 seconds to go from 54.8 ms to 12 ms what is the acceleration?

To find the acceleration of the train, we can use the formula: acceleration = (final velocity - initial velocity) / time. Given that the initial velocity (u) is 54.8 m/s, the final velocity (v) is 12 m/s, and the time (t) is 39 seconds, the acceleration can be calculated as follows: acceleration = (12 m/s - 54.8 m/s) / 39 s = (-42.8 m/s) / 39 s = -1.1 m/s^2. Therefore, the acceleration of the train is -1.1 m/s^2.


What is the elastic potential energy of a compressed spring when k is 17.7 newtons per centimeter and x is 19.0 centimeters?

U=1/2kx^2 = (1/2)(17.7N/cm)(19.0cm)^2 = 3194.85 N*cm = 3.195 N*m = 3.20 Joules