191 UNITED NATIONS MEMBER STATES
Let's use a combination of two equations F= ma and v= u + at where F= Force; m= mass; a= acceleration; v = final velocity= 0 m/s; u= initial velocity=25 m/s and t= time. From the equation v= u + at, we can solve for a. So, a = (v-u)/ t. Using F= ma F= m((v- u)/t)) F= 75kg((0-25 m/s)/ ls) F= (75 x 25) kg m/s^2 F= 1875 kg m/s^2= 1875 N
u= 0 m/s v= 200 m/s m= 20 kg F= 100 N F= (mv - mu)/t 100 = (20*200 - 20*0)/t 100 = 4000/t t= 4000/100 t= 40 s hope it helps cheers ^_^
Acceleration is defined as the change in velocity, divided by the time it takes to achieve this change. There are also some other formulas which you can use, depending on what you know about a specific situation.
Well, isn't that a happy little math problem we have here! To find the acceleration, we can use the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values, we get: acceleration = (12 - 54.8) / 39. So, the acceleration of the train is approximately -1.27 m/s². Remember, there are no mistakes in math, just happy little accidents!
U=1/2kx^2 = (1/2)(17.7N/cm)(19.0cm)^2 = 3194.85 N*cm = 3.195 N*m = 3.20 Joules
B-u-s-i-n-e-s-s-m-a-n
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Miss Louise McNaught
a-n-o-n-y-m-o-u-s
N - U - M - B - E - R - S.
Sunam
h t t p s : / / y a z i n g . c o m / d e a l s / b l u e h o s t / m a d i s o n a m u l l i n s
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Surmoon
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