Yes, it does. Your triangle has an area of 12.285 square inches and a perimeter of 23 inches.
Well, isn't that just a lovely measurement! 4 feet is equal to 48 inches, and when you add the extra 11 inches, you get a total of 59 inches. Just imagine all the beautiful things you could measure with that length!
71 inches equals 5.916666667 (5 11/12) feet.
150cm is 4 feet 11.1 inches.
A height of 4 feet 9 inches would be nearly 145 centimeters (144.78 cm or 1.4478 m). To convert, simply multiply the number of inches (in this case 57) by 2.54.
(4ft x 12in/1ft) + 11in = 48 + 11 = 59 inches
9, 4, and 11 are three dimensionless numbers. Yes, they can represent the lengths of the sides of a triangle. You can take three straight sticks, cut them to lengths of 9, 4, and 11 inches, then lay them down on a table so that the ends hook up and they form a triangle.
It is 22 in2. Multiply 4 by 11 and divide by 2.
A triangle with side lengths of 3, 4, and 5 inches is a scalene triangle.
Area of the triangle: 0.5*6*4 = 12 square inches
Yes
Let's get at the idea by working backward. Suppose we know the scale factor; what will the ratio of perimeters be? For instance, suppose we have two triangles; one has sides of 3, 4, and 5 inches; the other has sides of 33, 44, and 55 inches. The scalefactor is 11: you multiply each side length of the first triangle to get the corresponding side length of the second triangle. Now look at the perimeters. The perimeter of the first triangle is 3+4+5 = 12 inches. The perimeter of the second triangle is 33+44+55 = 132 inches. The ratio of perimeters is 132/12 = 11. Do you notice that it's the same as the scale factor? This will always be true! Here is why. We can write the sides of the second triangle as 3*11, 4*11, and 5*11. Then the perimeter is 3*11 + 4*11 + 5*11 = (3 + 4 + 5)*11 using the distributive property. To find the ratio of perimeters, divide this by the perimeter of the first triangle: (3+4+5)*11 ---------- = 11 3+4+5 Let's continue and think about the ratio of areas. The triangles I chose happen to be right triangles (do you know how to show this?) so the area is half the product of the two shorter sides. Thus the area of the first triangle is (3*4)/2 = 6 square inches. The area of the second triangle is (33*44)/6 = 726 square inches. The ratio of areas is 726/6 = 121. This ratio happens to be 11 squared. It will always be true that the ratio of areas is the square of the scale factor. Again, we can see why this is true. Writing the sides of the second triangle as 3*11 and 4*11, the area is 3*11 * 4*11 = (3*4)*(11*11) Divide this by the area of the first triangle to find the ratio of areas: (3*4)*(11*11) ------------- = 11*11 = 11^2 3*4 Do you see how it works now? What is the answer to your problem?
Area of triangle: 0.5*12*4 = 24 square inches
11, 4, 8
An equilateral triangle...
A triangle with sides of 4 inches!
It is 4 + 3 + 2 = 9 inches. Simple!
The perimeter of an equilateral triangle with a side length of 4 inches is 12 inches. Each side of an equilateral triangle is equal in length, so the perimeter is found by multiplying the side length (4 inches) by 3.