Just put both of them together use your common sense duh😂😂😂
BULLSHITISM!!
M1V1=M2V2
M1=0.5M
V1=250cm³
M2=2.5M
V2=?
M1V1=M2V2
M1V1/M2=V2
Putting the values
0.5×250÷2.5=V2
50=V2
Or
V2=50
Mix 20,01 ml 2 M solution with 80 mL demineralized water.
(m1v1 =m2v2 ) this formula will be used to find the answer
(XML)(2M) = (100ml)(0.4M)X = 20 ml
Well to make 30% stock solution of BSA from powder form you need to dissolve 30g of BSA into 100ml of solvent (water). Thus dissolved solution becomes 30% (w/v) stock solution.
a stock broker a stock broker
Common Stock is the most basic form of corporate ownership.
Materials come in stock forms so companies can keep stock on hand for when consumers and retailers need them. It also allows retailers to keep the most popular styles, colors, and quantities on-hand and simplifies re-ordering. Stock forms allow companies to keep prices down since orders for custom stock would cost more.
Calcium Carbonate
10 mg/ml stock solution
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
10-4
The answer is 20,15 mL.
0.15g of leishman powder dissolved in 100ml of distilled water
This depends on your experiment.
Well to make 30% stock solution of BSA from powder form you need to dissolve 30g of BSA into 100ml of solvent (water). Thus dissolved solution becomes 30% (w/v) stock solution.
(385 mL)(0.766 M NaOH) = (X mL)(4.03 M NaOH)4.03X = 294.91X = 73.2 ml============Take 73.2 mL of stock solution and add ( 385 mL - 73.2 mL = 311.8 mL) 312 mL of water to stock solution.
impossible....u want to use a low contrated solution to dilute into a higher contration solution? No way man,...
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.