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32% has a density of 11.04#/gal so 100 gal=1104#.

1104#*32%=353.28# of Nitrogen

To convert 353.28# of Nitrogen into a 28% solution instead of 32% you must divide the #of nitrogen by the new solution value to get total pounds of new soultion and the ability to subtraced the two values to determine the total dilutant needed:

353.28#N in 28% solution would be 353.28/28%=1261.71# 28% solution

1261.71# 28% -1104# 32%= 157.71# of dilutant (water) needed to make 28% soultion.

To figure out what percentace 32% is of the solution you divide the 32% solution weight by the new soultion weight:

1104/1261.71=.875 28% therefore is 87.5% of 32% by weight not volume.

To solve the problem you need to divide the original weight of 32% by its percentage in the new solution to get the total solution weight of the new solution and then subtract the original solution weight to get the amount of dilutant needed to dilute 32% to a 28% solution. Do the following:

(1104/.875)-1104=1261.71# of 28% solution. To dilulte 100 gal of 32% you will need to add water to get to the final weight of 28% solution

1261.71# 28%-1104# 32%=157.71# Dilutant (18.91 gal)

Finished product you will have 118.91gal of 28% weighing 1261.71#

28% solution will be 10.611#/gal

The fomula for this problem would be ((Galons 32% * 11.04)/.875)-(gal 32% * 11.04)= dilutant need. (gal 32% * 11.04)+ dilutant = # of 28% solution.

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Dallas Vaughn

Lvl 2
3y ago

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