There is a pseudo-code description of an algorithm at http://www.eecs.umich.edu/~qstout/abs/CACM86.html (the site explains the basic idea, and points to the paper that has the detailed algorithm). The tree produced is perfect, in that it has minimal height and a minimal number of nodes at the maximum depth. It is easy to turn the pseudo-code into code in any language. Quentin F. Stout A disclosure: it's one of my pages.
By making a simple ratio and using cross multiplication. I've included a simple equation to accomplish this... here's how this works.
You must wait until day time when the tree is casting a shadow. Take a stick or something else that is short enough to measure its height and push it into the ground vertically and straight. Measure the object's height, base to top, and its shadow, base to the end of the shadow. Make sure to right these numbers down because you will need them later.
Next, measure the shadow the tree is casting.
Now, using your recorded numbers, you can roughly estimate the trees height. Using this equation ---> (ObjectHeight * TreeShadow / Object Shadow = TreeHeight) should give you the trees height fairly accurately. Just make sure you make all your measurements in the same unit of measurement (i.e. inches, feet, cm, etc.)
The height of a tree would best be measured in metres.
The height would remain the same.
By unit of length and distance and conversion ,we can say that yes, kilometers can be used for measuring height.
Feet or metres would seem the most suitable.
Hold a yardstick perpendicular to the ground, and measure the shadow. Make a proportion, then measure the tree's shadow. Use the proportion to compute.
tree x width x height divided by 3
we can find the balance factor of highty balance tree with height of left subtree- height of right sub tree
Check this out! http://stackoverflow.com/questions/575772/the-best-way-to-calculate-the-height-in-a-binary-search-tree-balancing-an-avl
Tan60= 25/Height. Height = 25/Tan60 = 14.43
it can grow upto 400ft in height
Using trigonometery if you know the length of its shadow and angle of elevation
All i can find is that the The tree, usually a Norway Spruce (a pine i think) is about 75 to 90 feet (23 to 27 m) tall. Every year they erect a different tree i think, so the height varies.Cant find width :P
Formula for working out height of a tree is (distance from eye to base of tree/distance from eye to base of stick) x length of stick = tree height.(distance from eye to base of tree/distance from eye to base of stick) x length of stick = tree height is the formula for working out height of a tree.
The height of a complete binary tree is in terms of log(n) where n is the number of nodes in the tree. The height of a complete binary tree is the maximum number of edges from the root to a leaf, and in a complete binary tree, the number of leaf nodes is equal to the number of internal nodes plus 1. Since the number of leaf nodes in a complete binary tree is equal to 2^h where h is the height of the tree, we can use log2 to find the height of a complete binary tree in terms of the number of nodes.
The average height of a Joshua Tree is 17in.
A simple angle of elevation problem...You want to find out the height of a tree. You measure the distance from you to the base and find that it is 100 feet. You measure the angle of elevation of the top and find that it is 30 degrees. You are six feet tall. How tall is the tree?Answer: The tree is 64 feet tall. Its height is tangent 30 times 100 + 6.
the height is (20.5)