basically, the hitchhiker's thumb is a physical characteristic that is inherited from your mother and/or father.
when you were conceived, your mother gave you some of her genes, and your father gave you some of his.
the hitchhiker's thumb is either a dominent or recessive trait. It if is dominant, you could have a heterozygous parent and still have a 100% chance of inheriting it.
If the hitchhiker's thumb is recessive, you must have both of you parents homozygous for the gene to have a 100% chance of inheriting it.
The alleles are either HH (homozygous dominant), Hh (heterozygous), or hh (homozygous recessive).
H H << if the thumb is dominant trait, you have a 100% chance of getting it
H HH HH << if the thumb is recessive trait, you have a 0% chance of getting it
h Hh Hh
Heterozygosity implies possessing both a dominant and a recessive allele and the phenotype that is exhibited in a heterozygote is always the dominant one (hence the name 'dominant'). Therefore, if a phenotype is associated with heterozygosity, it is automatically the dominant phenotype.
Mendel showed in his experiments that inherited traits are not passed through the blending of inheritance theory. According to the blending of inheritance theory, an offspring's traits are a blend between the traits of the parent organisms. In Mendel's experiments however, he showed that this was not true, and that inheritance is actually based on genes, through the observation of recessive traits. He observed that an offspring could have a trait that neither of the parents had, which is now explained through both of the parents having the recessive gene for the trait, but not showing it because they are heterozygous dominant. There is a 25% chance that the offspring of two heterozygous dominant parents will produce a homozygous recessive offspring that will show the trait that neither of the parents shows.
the following refers to inorganic chemistry perspective tanabe-sugano diagrams can be used very easily determine the ligand field splitting (delta oct) and the racah parameter (B) accurately hence the energy of other absorptions of a complex can theoretically be determined
The question refers to the "following". In such circumstances would it be too much to expect that you make sure that there is something that is following?
Which of the following is not true about controls in an experiment
Genotype: AA - The phenotype is homozygous dominant, exhibiting the dominant trait. Genotype: Aa - The phenotype is heterozygous, exhibiting the dominant trait. Genotype: aa - The phenotype is homozygous recessive, exhibiting the recessive trait.
Cd because heterozygous means different and C and d are obvioulsy different
The results for the following can not be shown unless the following information is provided. Without this there is no way to show the results of it.
When they don't have pink as their color so the "parents" had to of been either both white or both pink. That is how you can tell when snapdragons are not following the pattern of complete dominance.
(Apex Learning) Bb.
However, you can veiw the chances of each color with this Foal Color Calaculator in the relatred links. The calculator said the following when I entered in the mare and the stud coats Offspring Color Probability 43.95% - Buckskin 43.95% - Bay 3.13% - Palomino 3.13% - Chestnut 2.93% - Smoky Black 2.93% - Black However, there were options to specify. It asked for Red factor and the Agouti, whether it was heterozygous or homozygous. I did not know these specifics, so I left it as unknown, which is why I advise you go and experiment. See what would happen if the stud was homozygous, or if the mare was homozygous, or if she was heterozygous, etc. YOu can only know with the vet usually....but its unknown...you wont know until the foal is born sorry.
It is called CODOMINANCE if the alleles each express when the phenotype is heterozygous. Let's look at the following situation. There are snapdragon flowers that are homozygous (having 2 of the same allele) for red. Let's call them R. There are also snapdragon flowers that are homozygous for white. Let's call them r. If you take one of the RR flowers and breed it with a rr flower, you will get Rr. If one of the alleles is dominant, then the flower will be the color of the dominant allele. If R (red) is the dominant allele, then all of the offspring will be red; if r (white) is the dominant allele, then they will be white. However, if they are codominant, then if the genotype is heterozygous (Rr), then the alleles will both express- in this case, the offspring would be pink. Hope I helped!
To set up keys for the described bird phenotypes, we can use the following designations: let "B" represent the allele for blue feathers and "b" represent the allele for white feathers. The blue feathered birds can be homozygous (BB) or heterozygous (Bb), while the white feathered birds are homozygous (bb). The medium trait, which is white with blue-tipped feathers, would be represented as heterozygous (Bb), indicating a blend of traits. Thus, the key would classify birds as blue (BB or Bb), medium (Bb), or white (bb).
That one.
The Hardy Weinberg equation is: p2 + 2pq + q2 = 1 Where p and q are the initial frequencies for the two alleles in question. This equation suggests that the three possible genotypes (homozygous p, heterozygous pq, and homozygous q) will reach a frequency equilibrium (i.e. stable frequency) in those proportions described above, if the following conditions are met: # Large population # No mutation # No selection# No emigration/immigration # Random mating In other words, evolution-- allelic frequency change within a population-- will not occur if the above 5 conditions are met.
The alleles such as TT or tt, RR or rr, and so on.The alleles such as TT or tt, RR or rr, and so on.they are also Tt Rr etc
Any recessive phenotype which is exhibited. Cystic Fibrosis requires both versions of the Cystic Fibrosis Transmembrane Conductance Regulator (CFTR) gene to be defective (i.e. they are homozygous) on both pairs of chromosome 7. Conversely having both normal CFTR genes is also an example of a homozygous configuration. Heterozygous would be having one normal and one defective gene i.e. being a carrier of the CF gene.