Approx. 37 g ammonia can be dissolved.
The complete question: Lead (II) oxide reacts with ammonia forming solid lead nitrogen gas and liquid water. 1.)How many grams of ammonia are consumed in the reaction of 75.0g lead (II) oxide? 2.) If 56.4g of lead are produced how many grams of nitrogen are also formed?
Does not compute! Grams is a measure of weight, ounces of water is a measure of volume.
1000 grams, assuming water density is 1000 gm/l
This question is misguided. I presume you mean how many spatula fulls of salt will dissolve in water. This is impossible to answer as it depends upon the mass of water, its temperature and the size of the spatula, and it's impossible to be completely consistent with what piles on the spatula. At 25 degrees C, 35.96 g of salt will dissolve in 100g of water.
17.636981_ounces"= 500 grams I'll provide the formula: 500 g*1 oz28.34952313 g=17.63698097 oz
Approximately 34 grams of KCl can dissolve in 100g of water at 30°C.
Approximately 42 grams of KCl can dissolve in 100 grams of water at 80°C.
There are 200 grams of ammonia in 200 grams of ammonia.
Approximately 56.7 grams of potassium bromide will dissolve in 100g of water at 70°C.
20
400
The amount of solute that will dissolve in water at a specific temperature depends on the solubility of the solute at that temperature. You need to check the solubility of the specific solute at the specified temperature (in degrees Celsius) to determine how many grams will dissolve in 100 grams of water.
Approximately 37 grams of ammonium chloride can dissolve in 100g of water at 50°C.
At 10°C, the solubility of strontium bromide (SrBr₂) in water is approximately 3.5 grams per 100 grams of water. This means that you can dissolve about 3.5 grams of strontium bromide in 100 grams of water at this temperature.
260
At 70 degrees Celsius, approximately 38 grams of potassium chloride (KCl) can dissolve in 100 grams of water. Therefore, in 200 grams of water, about 76 grams of KCl would dissolve. Keep in mind that solubility can vary slightly based on specific conditions.
Approximately 161 grams of lead nitrate will dissolve in 100mL of cold water at room temperature.