Area of pipe is: A = Pi X R^2 (pi times Radius Squared) Voume is Area of pipe Times Length of Pipe. Volume = L X A where Length is 288 inches. Volume = 288 X Pi X 4^2 = 14,476 cubic Inches Volume = 8.37 Cubic Feet
You need to know two things about the pipe; its length and inside diameter. Once you have that information the formula is:
V=Pi x r2 x h
Where:
V = Volume
Pi = 3.1415
r2 is the pipe's radius (1/2 the diameter) squared
h = length of the pipe
So, as an example, the volume in cubic feet of a 10-foot long pipe with and inside diameter of six feet would be calculated as follows:
V = 3.1415 x 32 x 10 (3.1415 x 9 x 10) which equals 282.735 cubic feet.
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Volume of a 240 foot long 1 inch internal diameter pipe is pi x 240 feet x 1/24 feet x 1/24 feet = approximately 1.31 cubic feet (about 2263 cubic inches).
The formula for this goes like this: radius of the pipe squared (32) x pi (3.1416) x length of pipe (12) = volume (amount of water). So 32 x 3.1416 x 12 = 339.2928 or about 339.3 cubic inches.
1 gallon = 231 cubic inches This is a pretty skinny pipe. Diameter = 1.5 inches Radius = 0.75 inch Unit length = 1 foot = 12 inches Volume = pi R2 L = pi x (0.75)2 x 12 = pi x (0.5625) x 12 = 6.75 pi = 21.206 cubic inches = (21.206 / 231) = 0.0918 gallon per foot You need 130.7 inches = 10ft 10.7in of this pipe to hold 1 gallon.
See frictionlosscalculator.com. They have a good description of friction loss I fire hose.
Pipe lengh. a 32' pipe CCCC would produce a ferquency of about 16hz. a 64' pipe CCCCC, 8hz similarly a 16' CCC, 32hz.
12 inches = 1 foot
0.61 * d2 Where d is the diameter of the pipe in inches.
Volume = pi R2 L = pi (2)2 x 120 cubic inches / (231 cubic inches per gallon)The volume (capacity) of the pipe is 6.528gallons. (rounded)
pi*r^2*h gives the volume of a foot long one inch pipe. Radius is 0.5 inches, height is 1 foot/12 inches. So the volume is 9.42 cubic inches. 9.42 (cubic inches) = 0.0407792208 US gallons
Just search for the numerous questions about the volume of a cylinder. Note that a 2-in pipe has a radius of one inch.
ninety four
A four-foot diameter pipe that is five feet long has a volume of 470 gallons.
A 1-foot length of a pipe with an 1-inch internal diameter will hold pi*r2*h cubic inches where r = 0.5, h = 12 So 9.42 cubic inches.
231 cubic inches. So 0.832674 Gallons.
You multiply the radius of the circle 0.5 (radius of a 1 inch pipe) by 3.14(pi) by the height of the pipe 12 inches which gives you 18.84ozs.
The capacity of one foot of a pipe with an inner diameter of 20 inches is approx 1.36 US gallons. The maximum amount of water is, therefore, 1.36 gallons, but there need not be any water in the pipe.
A piece of pipe is 303/4 inches long. If five pieces, each 41/3 inches long, are cut from the pipe, how many inches of pipe remain?