8550psi
60 cal merely means the size of the projectial fired. that cal was used during the civil war
You use Heat of fusion... Heat=mass x heat of fusion Heat of fusion for water: 80 cal/g so 35g x 80 cal/g= 2800 cal released.
No, to convert from cal. to joules 1 cal. = 4.18400 joules , then 1KCal = (4.18400 *10^-3) joules so 3.25 kcal doesn't equal 3.25 Joules
200000 calories. 1 gm of water needs 1 cal(calorie) to raise it's temperature through 10C. Now, density of water = 1gm/ml at 40C and we assume that it's density is same at 00C. So we have 2000gm of water. For raising temp by 10C we need 2000 cal. For raising temp by 1000C we need 2000 x 100 cal = 200000 calories
The specific heat of water is 1 calorie per gram per degree Celsius 1 cal/g/degree celsius
well all materials are bullet proof,that is depending on the caliber bullet and how thick the material is,a .22 caliber can pierce a 2x4,and a .50 cal can pierce about 50 2x4's,even paper can stop a bullet,if ya take one sheet of paper its not going to do much,but get about 1000 sheets and nothing can get threw,not even armor piercing!
Best left to a gunsmith
The cost of a 50 cal. BMG bullet is about $3,000 if you go to the right store!!
Around 4 dollars a round
From 2 to 4 dollars
22. cal bullets bro its pretty self explainatory
What about it?
what type bullet in 50 cal
If you mean how heavy is the bullet in a .40 caliber cartridge, the answer is, it ranges from about 150 grains to about 180 grains.
The proper term is CARTRIDGE- bullet is the part of a cartridge that is fired from the barrel. There is no one answer to your question- it will depend of which .50 CAL cartridge- and then it depends on the loading of that particular cartridge (different bullet weights will have different powders/ amounts)
22 cal 224 dia bullet.
The bullet itself - no.