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F = mg + ma

F = (1200)(9.8) + (1200)(0.90)

F = (1200)(9.8 + 0.9)

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T=m*a. m=1900kg, a=(0.80+9.8)m/s/s. T=20,140N

Q: How much tension must a rope withstand if it is used to accelerate a 1900 kg car vertically upward at 0.80 ms2?

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The adhesive forces of the polar water molecules to the glass surface, breaks the surface tension of the water and causes a capillary action up the sides of the tube.

As you leap upward from the ground, the force exerted on the ground in the moment of leaping is greater than your weight. This allows you to accelerate upwards. Gravity, of course, will bring you back down, causing another momentary force on the ground in excess of your weight as you decelerate.

270 N if in the same direction add if oposite subtract

ITS LIKE WHEN THERE IS A STICK STUCK DOWNWARD INTO THE GROUND AND YOU WANT TO TAKE IT OUT. YOU WILL PULL IT UPWARD. Sorry for capitalisation.. Hope this helped, :D

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Related questions

F=m*(g+a)=1600*(9.8+.7)=16800N

15875 The formula is F=m(a+g) F=1500(0.80+9.80)N F=15900N

it depends on how long the car will have to withstand that acceleration since there are also other factors like atmospheric drag. First second: kg = kilogram N = Newton 1kg = 9,81N 1800kg = 17.658N Force on the rope: 17658.0 x 0,6 = 10.594,8N = 10.595N 10.595N / 9,81 = 1080kg Your rope must withstand at least 1080kg or 10.595N for the first second. IT--

Any upward force greater than 78 lbs will accelerate that person vertically upwards.

Vertical means straight up and down,aligned with the direction of gravity. Vertically upward means vertical in the up direction. So if you jump directly straight up that is vertically upward; when you land you are travelling vertically downward.

a cricket ball is projected vertically upward direction.what kind of acceleration is acting on it

because if gravity

UPWARD UPWARD UPWARD

due to surface tension

The box would accelerate upward.

If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t âˆ’ 16t^2.

It's not. If the forces on an apple were unbalanced, then the apple would accelerate. As long as the apple is on the tree, the downward force of gravity is balanced by the upward tension in the stem. When the upward tension in the stem goes away, the forces are no longer balanced, and the apple accelerates in the direction of the remaining unbalanced net force. It continues accelerating in that direction until it hits the ground, whereupon the ground begins to provide an upward normal constraint force, which once again balances the force of gravity, and the acceleration ceases. All of this takes place without the slightest awareness on the part of the apple.