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F = mg + ma

F = (1200)(9.8) + (1200)(0.90)

F = (1200)(9.8 + 0.9)

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11y ago
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12y ago

T=m*a. m=1900kg, a=(0.80+9.8)m/s/s. T=20,140N

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Q: How much tension must a rope withstand if it is used to accelerate a 1900 kg car vertically upward at 0.80 ms2?
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