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F = mg + ma

F = (1200)(9.8) + (1200)(0.90)

F = (1200)(9.8 + 0.9)

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11y ago
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12y ago

T=m*a. m=1900kg, a=(0.80+9.8)m/s/s. T=20,140N

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Q: How much tension must a rope withstand if it is used to accelerate a 1900 kg car vertically upward at 0.80 ms2?
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How much tension must a rope withstand if it is used to accelerate a 1500 kg car vertically upward at 0.80 ms2?

15875 The formula is F=m(a+g) F=1500(0.80+9.80)N F=15900N


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To calculate the tension in the rope, you need to consider the force needed to overcome the gravitational force on the car plus the force required to accelerate the car. The tension in the rope can be found using the equation T = mg + ma, where T is the tension, m is the mass of the car, g is the acceleration due to gravity, and a is the acceleration of the car. In this case, the tension in the rope would be T = (1600 kg * 9.8 m/s^2) + (1600 kg * 0.70 m/s^2).


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