1 gallon = 128 fluid ounces 1/50 of a gallon = 2.56 fluid ounces
1 tsp in ten gallons .. so to find out how much is one gallon divide by 10. 1/10 = 0.1 so if it is 0.1 tsp per gallon then 3 gallons will take 0.1*3 = 0.3 of a teaspoon.
Well, sugar, a gallon of red meat doesn't weigh the same as your last bad date. A gallon of red meat weighs approximately 8 pounds, give or take a few ounces depending on the type of meat and its fat content. Just remember, darling, it's best to measure your meat by the pound, not by the gallon.
It takes 1 gallon
About 3 pounds. More if you are wearing a heavy coat.
You pour four gallons into the five gallon drum, and take the ten gallon drum with the other four gallons of oil in that.
after much thought, and some research on wikipedia (i take it you're asking about a standard 34.5" height, 24" diameter drum), i found it to have an buoyancy of about 12N; which would give it a lifting capability of about 117.728kg
The formula is as follow you take the size of the drum multiply it by the weight of water 8.34 and multiple the specfic gravity of the product you are using you can get that by looking at the MSDS of the material. 55Gal. X 8.34 X .93 = 426.591 would be the weight of a 55 gallon drum of Thinner.
This depends on many factors.
About 7 bushels
To determine how many 80-pound bags of concrete are needed to fill a 55-gallon drum, first calculate the volume of the drum. A 55-gallon drum holds about 7.4 cubic feet (since 1 gallon is approximately 0.133 cubic feet). An 80-pound bag of concrete typically yields about 0.6 cubic feet. Therefore, you would need approximately 12 to 13 bags of concrete to fill the drum.
The time it takes to boil a 55-gallon drum of liquid depends on the heat source and the starting temperature of the liquid. It could take several hours to bring that amount of liquid to a boil using a standard heating element.
Assuming that the drum itself has no mass and weight, calculate the mass of the liquid in which you want to place the drum. Use the formula: mass = density x volume The amount of mass to sink the drum will have to be that amount, or more.
A 30 gallon drum, of course, holds 30 gallons. This means that in order to sink this barrel in water you would have to displace 30 gallons of water. (move the water out of the way to make room for this drum) Each gallon of fresh water weighs 8.34 pounds. So if you were to totally sink this sealed drum in fresh water it would take 250.2 pounds of weight to do so. If you were to use these barrels for a pontoon boat or the like, I would suggest that you only use the barrels to a submersion level of 50%. This gives you some fudge-factor for weight distribution and walking around without having that "sinking" feeling. In salt water, you have to know the composition of the salt water, or the ratio of salt to water. Roughly, salt water weighs 64 lbs/cu. ft., as opposed to fresh water, which is about 62.2 lbs/cu. ft. There are 7.48 gallons in a cubic foot. So a gallon of salt water weighs 8.556 lbs. This means that in order to sink the drum you would have to displace more weight because salt water is heavier than fresh water which in turn will make your drum more buoyant. It would take 256.7 pounds to totally sink your drum in salt water. Keep in mind that a 30 gallon steel drum weighs between 30 and 40 pounds depending on the thickness of the steel when it was manufactured. This weight will need to be deducted from the total buoyancy. Of course plastic drums weigh less so do your math accordingly. In fresh water minus the steel drum weight of 35 pounds: 100% sinking = 215.2 lbs per drum 75% sinking = 161.4 lbs per drum 50% sinking = 107.6 lbs per drum In salt water minus the steel drum weight of 35 pounds: 100% sinking = 221.7 lbs per drum 75% sinking = 166.3 lbs per drum 50% sinking = 110.9 lbs per drum
take it to coinstar and get coin count and multiply each respective coin to its mint weight and voila
A metal fifty-five gallon lube oil drum is thirty five inches tall. Given: Area of a circle = 1/4piDiameter2 and: 231in3 / gallon Take the square root of: 55 gal x 231in3 / gallon x 4 / 35in / pi I come up with about 21.5 inches for the diameter, which sounds about right. But of course individual drums vary a bit, so grab a tape measure if you have a drum handy.
To calculate the volume of concrete needed to fill a 55-gallon drum, you first need to know the dimensions of the drum. Once you have the dimensions, you can use the formula for the volume of a cylinder (V = πr^2h) to calculate the volume of concrete required. Remember to convert the volume from gallons to cubic inches or feet for accurate results.