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Assuming the shape is a regular rectangle, then the width of each side will be equal to (22 - (10 x 2))/2 = 1 inch.

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Q: If the length is 10 inches and the perimeter is 22 inches what is the width?
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The pencil length is usually around 20 centimeters.


How many linear inches in 19 x 11 x 10?

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What is the difference between cubic inches and inches?

cubic inches is a unit of volume already. If you know how many cubic inches something takes up, then you know it's volume. ALTERNATE ANSWER: This depends on the volume that you are trying to calculate. In general, you take the formula for the volume, and plug in your units in inches. The result will be in cubic inches. FOR EXAMPLE: The formula for the volume of a sphere is 4/3 * PI * r^3. If the radius is 254 centimeters, we have to convert to inches first: 1 inch = 2.54 centimeters Using dimensional analysis, we have 254 centimeters * 1 inch / 2.54 centimeters = 100 inches. Now plug in r = 100 inches: 4 / 3 * PI * 100^3 = 4 / 3* PI * 100 * 100 * 100 = 4/3 * PI * 1,000,000 which is ~4,188,790.2 cubic inches. MUCH EASIER EXAMPLE: The volume of a cube is the s^3, where s is the length of it's side. So if the length of the side is 10, then your answer is 10 * 10 * 10 = 1,000 cubic inches.


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Related questions

What is the perimeter of a rectangle with the length of 3 inches and the width of 2 inches?

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What is the length and width of a rectangle that has a perimeter of 20 inches and an area of 24.4524 square inches showing work with final answers?

What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in


What is the area of a rectangle with a perimeter of 36 inches and a length of 5 inches?

With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches


What is the perimeter of a rectangle with length 10 miles and width 5 miles?

The perimeter of a rectangle with length of 10 miles and width of 5 miles is 30 miles.


What is the length and width if the perimeter is 352 and the length is 10 times the width?

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What is the formula for a rectangle?

Perimeter: (length: 5 inches; width: 5 inches) P= (2xL) + (2xW) P= (2x5) + (2x5) P= 10 + 10 P= 20 Area (length: 5 inches; width: 5 inches) A= LxW A= 5 x 5 A= 25


What is the perimeter of a rectangle that is 10 inches wide and 12 inches long?

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How do you find the width of a rectangle if length and perimeter are given?

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What is the length of a rectangle when the perimeter is 60 and the length is twice the width?

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What is the perimeter of a rectangle if the length is 10 and the width is 8?

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Perimeter = 15+10+15+10 = 50 units of measurement.


What is the perimeter and area of a rectangle that has a length of 12 inches and a width of 10 and a half inches?

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