Assuming the shape is a regular rectangle, then the width of each side will be equal to (22 - (10 x 2))/2 = 1 inch.
21
The pencil length is usually around 20 centimeters.
The answer will depend on several things for which no information is available:The units of measurement for the numbers which are given in the question.The context. In some cases, it is only the length (for example, wooden boards, wall covering, carpets) in others it is the sum of the length, width and height (airlines luggage).
Exactly 40+10+40+10 = 100cm which is its perimeter
cubic inches is a unit of volume already. If you know how many cubic inches something takes up, then you know it's volume. ALTERNATE ANSWER: This depends on the volume that you are trying to calculate. In general, you take the formula for the volume, and plug in your units in inches. The result will be in cubic inches. FOR EXAMPLE: The formula for the volume of a sphere is 4/3 * PI * r^3. If the radius is 254 centimeters, we have to convert to inches first: 1 inch = 2.54 centimeters Using dimensional analysis, we have 254 centimeters * 1 inch / 2.54 centimeters = 100 inches. Now plug in r = 100 inches: 4 / 3 * PI * 100^3 = 4 / 3* PI * 100 * 100 * 100 = 4/3 * PI * 1,000,000 which is ~4,188,790.2 cubic inches. MUCH EASIER EXAMPLE: The volume of a cube is the s^3, where s is the length of it's side. So if the length of the side is 10, then your answer is 10 * 10 * 10 = 1,000 cubic inches.
10 feet 7 inches is 127 inches.
10 inches
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches
The perimeter of a rectangle with length of 10 miles and width of 5 miles is 30 miles.
Length Plus width = half of perimeter = 176. Width is one-eleventh of this and length is ten-elevenths ie 16 and 160 respectively.
Perimeter: (length: 5 inches; width: 5 inches) P= (2xL) + (2xW) P= (2x5) + (2x5) P= 10 + 10 P= 20 Area (length: 5 inches; width: 5 inches) A= LxW A= 5 x 5 A= 25
P = 2(length) + 2(width) P = 2(12 inches) + 2(10 inches) P = 44 inches
multiple the length by 2 then subtract that from the perimeter. then divide that by two. for example length=10 perimeter=30 ... 30-2(10)= 30-20=10 10/2=5 width=5
The length is 20 units and the width is 10 units
2 sides have length 10 and the other 2 sides have width 8 perimeter is sum of sides = 10+10+8+8 = 36
Perimeter = 15+10+15+10 = 50 units of measurement.
Perimeter = 2*(L + W) = 2*(12 + 10.5) = 2*22.5 = 45 inches. Area = 12*10.5 = 126 square inches.