it would be better to use a 0 - 200 n scale cause elephants enjoy eating frosted canabals for brunch at approx 2 pm
medicine
Could you explain the question better, not clear what it is asking
it is the scale to find the mass of a thing even liquid and solid
Temperature is the measure of how fast particles are moving in an object.
A balanced scale, which compares the mass of one object with that of a known quantity.
klfjlky
True
A scale is a force indicator. The reading on a scale is simply telling you what force is being applied. If you try dragging an object across the floor using a spring scale, you are applying a force to the spring scale which is applying a force to the object. The spring scale cannot put more force on the object than you are putting on the scale, and it has to put all of the force that you put on it on the object you are pulling. The only other force on the object besides your pulling force is friction. If the object is traveling at a constant velocity, the forces on it are equal. That means that your pulling force has to equal the force of friction. The scale that you are using will read the amount of force you are putting on the object which will tell you how much friction is pulling backwards on the object because these forces are equal strengths.
about 1,800 g A+
The force exerted on a scale by an object and other forces acting.
Here is a sentence: The pH scale is the measurement of how basic an object is or how acidic an object is.
scale drawing
[object Object]
A scale is used to measure a weight of an object
A scale drawing.
A scale drawing!
-- The scale itself is accelerating vertically, either upward or downward.-- The scale and object are falling.-- The scale and object are in an elevator which is either just starting out or just coming to rest.-- The scale and object are on a space vehicle during or after launch, or in transit, or during re-entry or landing.-- The scale and object are on the moon, or on another planet. In either of these cases, the scale readsthe correct 'weight', but it's not the reading you expect, since it's not the object's earth weight.