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10x to 1x is a 1:10 dilution Therefore, add 1 part buffer, 9 parts DI-water If 100uL is 10uL (1 part buffer) and 90uL (9 parts DI-water) Then, 200ul (100 x 2) is 20uL (1 part buffer) and 180uL (9 parts DI-water)

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Q: In this procedure a 10x buffer is used if you have a 5x buffer and you want a total volume of 200ul what dilution would you perform to achieve the desired 1x concentration of buffer?
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