Sol: 24 = 3 x 8, where 3 and 8 are co-primes.
The sum of the digits in the given number is 36, which is divisible by 3. So, the
given number is divisible by 3.
The number formed by the last 3 digits of the given number is 744, which is
divisible by 8. So, the given number is divisible by 8.
Thus, the given number is divisible by both 3 and 8, where 3 and 8 are co-primes.
So, it is divisible by 3 x 8, i.e., 24.
Sol. Since the given number is divisible by 5, so 0 or 5 must come in place of $. But, a number ending with 5 is never divisible by 8. So, 0 will replace $. Now, the number formed by the last three digits is 4*0, which becomes divisible by 8, if * is replaced by 4. Hence, digits in place of * and $ are 4 and 0 respectively.
ten
The simple answer for 'is it divisible by three?' is to add the digits together, and if the total can be divided by three, then the original number can be. Otherwise, no. So, 1+7+0 = 8 which is not divisible by three, so 170 itself is not. Assuming you require no remainder.
24 C = 32 + (24 x 1.8) F = 32 +43.2 F = 75.2 Fahrenheit
24
No, 157 is not divisible by 24.
No. 24 is not evenly divisible by 20.
Yes. 24 divided by 9 is 3. ^^^WRONG ! 24 is NOT divisible by 9 !
No, 2 is not evenly divisible by 24.
No. On a scientific calcultor, 9 divided by 24 should come out as 0.375, but overall, no - 24 is not divisible by 9.
Becuz 8 mutiplied by 3 is 24
No, 24 is not divisible by 10.
Yes 1124 is divisible by 4. Since 24 is divisible by 4 1124 is divisible by 4. If the last two numbers of a number are divisible by 4, the number is divisible by 4. 24 divided by 4 is 6.
24, and any multiple of 24 would be divisible by both 3 and 8.
24 is divisible by all of them. But only 2,3,4,6 & 8 will return whole numbers.
Yes.
Numbers divisible by 24 are those that can be divided by 24 without leaving a remainder. Some examples of numbers divisible by 24 include 24, 48, 72, 96, 120, and so on. This is because 24 is a multiple of 1, 2, 3, 4, 6, 8, 12, and itself, so any number that is a multiple of 24 will also be divisible by these factors.