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If a shoe is dropped from a height of 40m what is its speed after falling for two seconds?
Regardless of the height from which it is falling, (neglecting air resistance) it's speed will be 19.62 metres per second. (Acceleration from gravity is 9.81 metres per second squared, so after 1 second it is moving at 9.81 metres per second and after 2 seconds it is moving at 19.62 metres per second.
How many kilometers does sound travel in seconds?
Use the standard equation for speed:distance = speed x time Solving for time: time = distance / speed
A baseball is seen to pass upward by a window 25M above the street with a vertical speed of 12ms if the ball was thrown from the street what was its initial speed?
for this problem use the formula V(final)= V0 +A*t V0=36ms V(final)= 12ms A= -9.8m/s^2 t=? plug into the equation 12= 36 + (-9.8)t -24= (-9.8)t t=2.4 seconds
What is the speed of a rocket that travels 8000 meters in 12 seconds?
8000m/12sec.
What is the speed of an object weighing 80 pounds dropped from 7 feet?
it strikes the ground at a velocity of 17.9 ft/s
What is the speed of an object that is dropped off a cliff after 5 seconds and no air resistance with an initial speed of 0 ms?
The speed of an object dropped off a cliff after 5 seconds, neglecting air resistance, is given by the equation: v = gt, where v is the final speed, g is the acceleration due to gravity (9.8 m/s^2), and t is the time it has been falling. Plugging in the values gives v = 9.8 m/s^2 * 5 s = 49 m/s. So, the speed of the object after 5 seconds will be 49 m/s.
Suppose a rock is dropped off a cliff with an initial speed of 0 ms. What is the rock's speed after 5 seconds in ms if it encounters no air resistance?
The rock's speed after 5 seconds would be approximately 49 m/s. This is calculated using the formula v = g * t, where v is the final speed, g is the acceleration due to gravity (9.8 m/s^2), and t is the time elapsed (5 seconds).
How do you find the height of the tower given only 8 seconds stone is dropped?
distance = speed x time so the distance is just the speed of the stone x 8 seconds
A rock dropped on the moon will increase its speed from 0 ms its starting speed when first dropped to 4.9 ms in about 3 seconds What value do you calculate for the magnitude of the acceleration o?
1.63 m/s2
Suppose a rock is dropped off a cliff with an initial speed of 0 What is the rock's speed after 5 seconds in if it encounters no air resistance?
49
It takes 6seconds for a stone dropped from rest to hit the bottom of a well what is its final speeds?
Using the equation of motion s = ut + (1/2)at^2, where s is the distance, u is the initial velocity, a is acceleration, and t is time, we can find the final speed. We know that initial velocity, u, is 0 as the stone is dropped from rest. The acceleration, a, would be due to gravity (-9.8 m/s^2). Rearrange the equation to find final speed, v: v = at. Plug in the values: v = 9.8 m/s^2 * 6s = 58.8 m/s. So, the final speed of the stone when it hits the bottom of the well is 58.8 m/s.
A rock dropped on the moon will increase its speed from 0 its starting speed to 8.15 in about 5 seconds If you were standing on the moon measuring the rock's motion what would you measure?
That works out at an acceleration of 1.63 m/s2(Presumably you meant 8.15 meters per second.)You would measure how far the rock dropped in 5 seconds. Then you could work out the final speed (or acceleration) from the "equations of motion".
If a car can go 0 to 60 mph in 8 seconds what would be its final speed after 5 seconds if its starting speed were 50 mph?
87.5mi/hr2
Suppose a rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 3 seconds in ms if it encounters no air resistance?
29.4
Suppose a rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 5 seconds in ms if it encounters no air resistance?
49
What happened to the speed of the ball during the final 2 seconds?
The speed of the ball during the final 2 seconds likely decreased as it experienced air resistance and friction from contact with the ground. Without additional information, we can only infer that the ball's speed reduced gradually until it came to a stop.
A marble dropped from a bridge strikes the water in 5 seconds. What is the speed with which it strikes and the height of the bridge?
Velocity final = vi + at = 49 m/s displacement = vi * t + ½2at² = 122.5 m vi = 0 a ≈ 9.8 t = 5
