60 m/s
Regardless of the height from which it is falling, (neglecting air resistance) it's speed will be 19.62 metres per second. (Acceleration from gravity is 9.81 metres per second squared, so after 1 second it is moving at 9.81 metres per second and after 2 seconds it is moving at 19.62 metres per second.
Use the standard equation for speed:distance = speed x time Solving for time: time = distance / speed
for this problem use the formula V(final)= V0 +A*t V0=36ms V(final)= 12ms A= -9.8m/s^2 t=? plug into the equation 12= 36 + (-9.8)t -24= (-9.8)t t=2.4 seconds
8000m/12sec.
it strikes the ground at a velocity of 17.9 ft/s
That works out at an acceleration of 1.63 m/s2(Presumably you meant 8.15 meters per second.)You would measure how far the rock dropped in 5 seconds. Then you could work out the final speed (or acceleration) from the "equations of motion".
distance = speed x time so the distance is just the speed of the stone x 8 seconds
1.63 m/s2
87.5mi/hr2
49
The speed is 44.4... repeating metres per second.
29.4
49
Velocity final = vi + at = 49 m/s displacement = vi * t + ½2at² = 122.5 m vi = 0 a ≈ 9.8 t = 5
A marble traveling at 3.0m/s starts to acceleration at 4.5m/s over a distance of 25m. what is the final speed of the marble?
25mph
speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s