Ka for acrylic acid is 0.000056 calculate the pH of 0.10m aqueous solution of acrylic acidCalculate percent dissociation of 0.10m solution of acrylic acid?

Answer 1

Ka = ([H+][A-])/[HA]) Let concentration of dissociated acrylic acid be x. 0.000056 = (x2)/(0.10 - x) Rearrange: 0.0000056 - 0.000056x - x2 = 0 x = 0.002339 Therefore: [H+] = 0.002339 M pH = -log[H+] = 2.63 Percent dissociation: 0.002339/0.10 = 0.02339 = 2.34 %