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Change in temperature, dT,=1/m, where m is the amount of water, in kilograms.

Depends on how much kilograms of water you have. The equation to use is Q=cm(dT), where c is the specific heat capacity of water (conventional use puts it 4186 J/(kg*C degrees)), m is the mass, in kilograms, of the water you're heating, dT is the amount of degrees, in Celsius (or Kelvin), that you want to heat the water by, and Q is the amount of energy needed, in Joules. 1 kilocalorie equals 4186J, solving for change in temperature (dT), dT=Q/(cm). Substituting in Q and c gives you dT=1/m. If you do not know the mass, but only volume, m=pV, where p is the density of water (convetionally 1 *10^3 kg/m^3) and V is the volume of the amount of water you have in m^3.

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What is substances specific heat?

The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!


What energy unit is defined as the heat required to raise on kilogram of water by one degree Celsius?

I believe it is Calorie.


Does water always freeze at 0 Celsius?

Pure water at stp will freeze at zero degrees Celsius. However, it is possible to change this by altering the pressure of the water. Decreasing the pressure will raise the freezing point slightly.


How much heat does a kilowatt have?

A watt is a measure of energy, which may or may not be heat, but heat is considered to be the simplest form of energy and is an easy way to compare amounts of energy. Another measure of energy that is easy to work with is a calorie, which is the amount of energy needed to raise the temperature of 1 gram of water by 1 degree C. In these terms without special conditions, this applies only between 0 and 100 degrees C, because freezing and boiling make the equations much more complicated. A watt is approximately 86 calories, meaning that applied to a gram of water would raise its temperature by 86 degrees centigrade. A kilowatt is 1000 watts meaning that it could raise the temperature of that gram of water by 86000 degrees--at least theoretically, but that image is all but useless. So let's say that a kilowatt represents enough heat to raise the temperature of a liter (1000 g) of water by 86 degrees C.


Specific heat capacity of water?

The specific heat of water is 4.184 J/g*°C, which is read 4.184 Joules per gram degree Celsius. It can also be stated as 1.00 cal/g*°C, which is read calories per gram degree Celsius (same as centigrade). These values mean that it takes 4.184 Joules of energy to raise the temperature of 1 gram of water 1 degree Celsius. Or it takes 1.00 calories of energy to raise the temperature of 1 gram of water 1 degree Celsius. 4.184 Joules = 1.00 calorie

Related Questions

How much energy would you use to raise temperature of kg of water by 2 degrees Celsius?

The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.


What is the differences between Calorie and kilo calorie?

A calorie is the unit of energy required to raise one gram of water 1 degree Celsius. A kilocalorie, or Calorie, is the equivalent of 1000 calories.


What is meant by kcal?

This is the abbreviation for kilocalorie, the metric name for one thousand calories. thus, 1.0 kcal = 1,000 cal Kilocalorie is the amount of heat energy require to raise 1 kilo or 2.2 pounds of water one degree Celsius ( centigrade ). Similarly, a calorie is the amount of heat energy required to raise one cubic centimetre of water one degree.


What is the amount of energy needed to raise the temperature of 1 gram of water by 1 degrees Celsius?

The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.


How many joules does it take to raise temperature from 30 degrees Celsius to 45 degrees Celsius?

To raise the temperature of a substance, you need to calculate the heat energy using the specific heat capacity of the substance. Without knowing the specific heat capacity of the substance in question, it's not possible to determine the exact amount of energy required to raise the temperature from 30 to 45 degrees Celsius.


How many liters of cold water from the fridge at 4 degrees Celsius would you have to drink to burn 330 kilocalories to heat it up to body temperature at 37 degrees Celsius?

To raise the temperature of 1 liter of water by 1 degree Celsius, it requires 1 kilocalorie. Therefore, to burn 330 kilocalories and heat cold water from 4 degrees Celsius to 37 degrees Celsius, you would need to drink 33 liters of cold water.


How much energy is required to raise the temperature of 3kg of iron from 20 degrees Celsius to 25 degrees Celsius?

The specific heat capacity of iron is 0.45 J/g°C. To raise the temperature of 3kg (3000g) of iron by 5 degrees Celsius, you would need: 3000g x 0.45 J/g°C x 5°C = 6750 Joules of energy.


What term describes the amount of thermal energy that is required to raise the temperature of a substance by 1.0 degrees Celsius?

Specific heat capacity is the term that describes the amount of thermal energy required to raise the temperature of a substance by 1.0 degree Celsius.


True or false a calorie is the amount of heat energy required to raise the temperature of 1 g of water 2 degrees C?

True. A calorie is defined as the amount of heat energy needed to raise the temperature of 1 gram of water by 1 degree Celsius.


What energy unit is defined as the heat required to raise one kilogram of water by one degrees celsius?

I believe it is Calorie.


What is the difference between calorie and kilo calorie?

A calorie is a unit of energy and is often used to measure the energy content in food. A kilocalorie (kcal) is equal to 1000 calories and is commonly used to represent the energy content of food. So when you see calories listed on a food label, they are usually referring to kilocalories.


How many kilojoules are there in a kilocalorie?

http://www.unitconversion.org/ 1 kilojoule = 0.239005736 kilocalorie 1 J = 0.2390 cal1 J= 0.239005736 cal 1 cal = 4.184 J1 cal =4.184000002 J