To find the midpoint, you find the mean (average) of each direction's coordinates. The average of the x coordinates is (9+7)/2 = 8. The average of y coordinates is (11+8)/2 = 9.5, So the midpoint is (8,9.5). This same method works for 3 and higher dimensions.
11 stone 7 pounds = 73.03 kilograms.
it is 1 7/8 inches
10 feet 11 inches is 3.33m
2,400 millimeters is 7 feet and 10.49 inches.
5/16" + 7/8" = 1.1875 inches. 5/16 + 7/8 = 5/16 + 14/16 = 19/16 = 1 3/16
The midpoint is at (7, 6)
For the distance, use the Pythagorean formula. For the midpoint, take the average of the x-coordinates, and the average of the y-coordinates.
If you mean: (-2, 3) and (8, -7) then the midpont is (3, -2)
Midpoint: (8, 7)
The midpoint is at: (10, -2)
midpoint: (8, 5)
The midpoint of the hypotenuse equidistant from all the vertices
The midpoint of the hypotenuse equidistant from all the vertices
Endpoints: (-8, -7) and (-7, -8) Midpoint (-7.5, -7.5)
To find the midpoint of the segment with endpoints H(8, 13) and K(10, 9), use the midpoint formula: ( M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) ). Plugging in the coordinates, we get ( M = \left( \frac{8 + 10}{2}, \frac{13 + 9}{2} \right) = \left( \frac{18}{2}, \frac{22}{2} \right) = (9, 11) ). Therefore, the coordinates of the midpoint are (9, 11).
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
The mid point is at the mean average of each of the coordinates: The midpoint between A (6,3) and and B (8,1) is (6+8/2, 3+1/2) = (7, 2)