To find the midpoint, you find the mean (average) of each direction's coordinates. The average of the x coordinates is (9+7)/2 = 8. The average of y coordinates is (11+8)/2 = 9.5, So the midpoint is (8,9.5). This same method works for 3 and higher dimensions.
11 stone 7 pounds = 73.03 kilograms.
it is 1 7/8 inches
10 feet 11 inches is 3.33m
2,400 millimeters is 7 feet and 10.49 inches.
5/16" + 7/8" = 1.1875 inches. 5/16 + 7/8 = 5/16 + 14/16 = 19/16 = 1 3/16
The midpoint is at (7, 6)
For the distance, use the Pythagorean formula. For the midpoint, take the average of the x-coordinates, and the average of the y-coordinates.
If you mean: (-2, 3) and (8, -7) then the midpont is (3, -2)
Midpoint: (8, 7)
The midpoint is at: (10, -2)
midpoint: (8, 5)
The midpoint of the hypotenuse equidistant from all the vertices
The midpoint of the hypotenuse equidistant from all the vertices
To find the midpoint of the segment with endpoints H(8, 13) and K(10, 9), use the midpoint formula: ( M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) ). Plugging in the coordinates, we get ( M = \left( \frac{8 + 10}{2}, \frac{13 + 9}{2} \right) = \left( \frac{18}{2}, \frac{22}{2} \right) = (9, 11) ). Therefore, the coordinates of the midpoint are (9, 11).
Endpoints: (-8, -7) and (-7, -8) Midpoint (-7.5, -7.5)
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
The mid point is at the mean average of each of the coordinates: The midpoint between A (6,3) and and B (8,1) is (6+8/2, 3+1/2) = (7, 2)