Well, honey, if the perimeter of a rectangle is 204 feet and the width is 45 feet, you can find the length by using the formula P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Plug in the values and solve for l. In this case, the length of the yard would be 57 feet.
5000 feet ********** 5000 square feet is the AREA of the park (i.e. length x width). The perimeter is the total distance around the outside edge (i.e. 100 + 50 + 100 + 50), which is 300 feet. Pretty small park!
432 square feet. Just multiply length by width - the answer is the square footage.
You need to know the width too.
No, just length X width.
it is 12 feet.
Perimeter = 2*(Length + Width) = 2*(15+9) = 48 feet.
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
The perimeter of a rectangle with a length of 8.5 feet and a width of 4.5 feet is 26.
If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
Length = 16 feetWidth = 8 feetDistance around the perimeter =Length + width + length + width = 16 + 8 + 16 + 8 = 48 feet.
The length is 3 feet
If the length to width ratio is 4 to 5 then the length to width ratio is 4 to 5no matter what the perimeter. If the perimeter is 70 feet then the sides are 15.555... and 19.444... feet respectively.
The perimeter is 30 feet for this rectangle.
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
22 feet